我编写了一个检查输入中的 4 个参数并在输出中显示结果列表的类。 此参数中只有一个是必需的,因此我有 7 个 if - else 嵌套 block 。 我想指定所述条件是否正常工作。
我在徘徊是否有更聪明的方式来写这个:
if cd['subject'] is None:
if cd['school'] == '':
if cd['price']:
files = File.objects.filter(name__contains=cd['name'], price = '0.0')
else:
files = File.objects.filter(name__contains=cd['name'])
else:
if cd['price']:
files = File.objects.filter(name__contains=cd['name'], school = cd['school'], price = '0.0')
else:
files = File.objects.filter(name__contains=cd['name'], school = cd['school'])
else:
if cd['school'] == '':
if cd['price']:
files = File.objects.filter(name__contains=cd['name'], subject = cd['subject'], price = '0.0')
else:
files = File.objects.filter(name__contains=cd['name'], subject = cd['subject'])
else:
if cd['price']:
files = File.objects.filter(name__contains=cd['name'], school = cd['school'], subject = cd['subject'], price = '0.0')
else:
files = File.objects.filter(name__contains=cd['name'], school = cd['school'], subject = cd['subject'])
return render(request, 'search.html', {'files': files, 'request': request})
最佳答案
在内部,您传递给函数的关键字参数只是一个dict
。所以自己构建它并使用 **name
语法将它传递给函数:
args = {}
args['name__contains'] = cd['name']
if cd['subject'] is not None:
args['subject'] = cd['subject']
if cd['school'] != '':
args['school'] = cd['school']
if cd['price']:
args['price'] = cd['price']
files = File.objects.filter(**args)
return render(request, 'search.html', {'files': files, 'request': request})
关于python - 如何避免太多 if - else block 在 python 中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20751124/