我想使用一个域作为多个 flask 应用程序的暂存环境,这些应用程序最终将在它们自己的域上运行。
类似于:
- example_staging.com/app1
- example_staging.com/app2
- example_staging.com/app3
哪里:
- example_staging.com/app1 与 app1.example_staging.com 相同
- example_staging.com/app2 与 app2.example_staging.com 相同
- example_staging.com/app3 与 app3.example_staging.com 相同
或:
- example_staging.com/app1 与 app1.com 相同
- example_staging.com/app2 与 app2.com 相同
- example_staging.com/app3 与 app3.com 相同
入门应用:
from flask import Flask
app = Flask(__name__)
@app.route('/')
def hello_world():
return 'Hello from Flask!'
WSGI 入门配置文件:
import sys
project_home = u'/home/path/sample1'
if project_home not in sys.path:
sys.path = [project_home] + sys.path
from app import app as application
引用:
http://flask.pocoo.org/docs/0.10/patterns/appdispatch/
我不知道在哪里添加文档中给出的示例代码以及 create_app、default_app、get_user_for_prefix 应该是什么样子。
注意:使用 PythonAnywhere
解决方案
Glenns 输入后的 WSGI 配置文件:
import sys
# add your project directory to the sys.path
project_home = u'/home/path/app1'
if project_home not in sys.path:
sys.path = [project_home] + sys.path
from werkzeug.wsgi import DispatcherMiddleware
from app import app as app1
from app2.app import app as app2
from app3.app import app as app3
application = DispatcherMiddleware(app1, {
'/app2': app2,
'/app3': app3
})
文件夹结构:
app1 folder
app2 folder
app3 folder
最佳答案
这对我有用:
文件夹结构
DISPATCHER (folder)
dispatcher.py
app1 (folder)
__init__.py
app2 (folder)
__init__.py
app3 (folder)
__init__.py
dispatcher.py
from flask import Flask
from werkzeug.wsgi import DispatcherMiddleware #use the commented version below for Werkzeug >= v.1.0
#from werkzeug.middleware.dispatcher import DispatcherMiddleware
from werkzeug.exceptions import NotFound
from app1 import app as app1
from app2 import app as app2
from app3 import app as app3
app = Flask(__name__)
app.wsgi_app = DispatcherMiddleware(NotFound(), {
"/app1": app1,
'/app2': app2,
'/app3': app3
})
if __name__ == "__main__":
app.run()
app1 到 app3 init.py
from flask import Flask
app = Flask(__name__)
@app.route("/")
def index_one():
return "Hi im 1 or 2 or 3"
if __name__ == "__main__":
app.run()
工作
python dispatcher.py
localhost:5000/app1 "Hi im one"
localhost:5000/app2 "Hi im two"
localhost:5000/app3 "Hi im three"
另一种配置
您可以导入另一个应用程序,例如 app0 并向应用程序添加菜单,使用 NotFound()
更改此设置
这有帮助
关于python - 如何使用 WSGI 实现 Flask 应用按路径调度?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30906489/