我是 golang 的新手。
我想在特定持续时间(现在为 1 秒)内精确地以 1 毫秒调用一个函数,该函数应该每秒调用 1000 次。
我确实使用 timer 和 tick 遵循并实现了多种方法,但是当测试一个每次调用时只增加一个值的简单函数时,我发现它在 1 秒内只被调用了大约 630 次。
当我在循环中调用该函数并在 1 秒后停止它时,该函数在 1 秒内被调用约 ~ 226370427 次,这意味着我的计时器和滴答有问题。
这是我使用 goroutine 并发实现的代码,它使用 ticker 调用每 1 毫秒递增一次的函数,并在 1 秒后由 main 停止,然后使用 int channel 读取总和值。
import (
"fmt"
"time"
)
func main() {
tickChan := time.NewTicker(time.Millisecond * 1).C
doneChan := make(chan bool)
resultChan := make(chan int)
go start(tickChan, doneChan, resultChan)
time.Sleep(time.Second * 1)
doneChan <- true // Set it to true to stop the infinte loop in the routine
fmt.Printf("total is : %v\n", <-resultChan)
}
func start(tickChan <-chan time.Time, doneChan <-chan bool, resultChan chan int) {
sum := 0 // <-- The the value to increment
for {
select {
case <-tickChan:
sum++
case <-doneChan:
resultChan <- sum
return
}
}
}
我能够在 node.js 中成功地做到这一点(使用 nanotimer lib)并且能够在每 1 毫秒内在 1 秒内准确地运行 1000 次,我什至也在微秒内完成了它(大约是 ~ 988676在 1 秒而不是 100 万 )
编辑:
这里是我的go版本 go version go1.10.2 windows/amd64
然后去环境 `
set GOARCH=amd64
set GOBIN=
set GOCACHE=C:\Users\name\AppData\Local\go-build
set GOEXE=.exe
set GOHOSTARCH=amd64
set GOHOSTOS=windows
set GOOS=windows
set GOPATH=C:\Users\name\Documents\Go Projects
set GORACE=
set GOROOT=C:\Go
set GOTMPDIR=
set GOTOOLDIR=C:\Go\pkg\tool\windows_amd64
set GCCGO=gccgo
set CC=gcc
set CXX=g++
set CGO_ENABLED=1
set CGO_CFLAGS=-g -O2
set CGO_CPPFLAGS=
set CGO_CXXFLAGS=-g -O2
set CGO_FFLAGS=-g -O2
set CGO_LDFLAGS=-g -O2
set PKG_CONFIG=pkg-config
set GOGCCFLAGS=-m64 -mthreads -fno-caret-diagnostics -Qunused-arguments -fmessage-length=0 -fdebug-prefix-map=C:\Users\name\AppData\Local\Temp\go-build403228958=/tmp/go-build -gno-record-gcc-switches
`
编辑 2:我在 Playground 上对其进行了测试,并设法获得了 1000 个总数,我认为问题出在 Windows 上。有什么办法可以解决它吗?
最佳答案
import "time"
A Ticker holds a channel that delivers `ticks' of a clock at intervals.
type Ticker struct { C <-chan Time // The channel on which the ticks are delivered. // contains filtered or unexported fields }
func NewTicker(d Duration) *Ticker
NewTicker returns a new Ticker containing a channel that will send the time with a period specified by the duration argument. It adjusts the intervals or drops ticks to make up for slow receivers. The duration d must be greater than zero; if not, NewTicker will panic. Stop the ticker to release associated resources.
这是我在同一台双引导机器上针对 Windows 10.0.17134 和 Linux 4.15 的结果。
package main
import (
"fmt"
"runtime"
"time"
)
func ticker(tick time.Duration) {
ticker := time.NewTicker(tick)
defer ticker.Stop()
done := make(chan bool)
sleep := 1 * time.Second
go func() {
time.Sleep(sleep)
done <- true
}()
ticks := 0
for {
select {
case <-done:
fmt.Printf("%v × %v ticks in %v\n", ticks, tick, sleep)
return
case <-ticker.C:
ticks++
}
}
}
func main() {
fmt.Println("GOMAXPROCS:", runtime.GOMAXPROCS(0))
start := time.Duration(1 * time.Millisecond)
end := start / 1000
for tick := start; tick >= end; tick /= 10 {
ticker(tick)
}
}
输出:
Microsoft Windows [Version 10.0.17134.112]:
GOMAXPROCS: 4
554 × 1ms ticks in 1s
552 × 100µs ticks in 1s
542 × 10µs ticks in 1s
552 × 1µs ticks in 1s
Linux 4.15.0-23-generic:
GOMAXPROCS: 4
1000 × 1ms ticks in 1s
9990 × 100µs ticks in 1s
13169 × 10µs ticks in 1s
14014 × 1µs ticks in 1s
Sleep function | Microsoft Docs
Suspends the execution of the current thread until the time-out interval elapses.
Parameters
dwMilliseconds
The time interval for which execution is to be suspended, in milliseconds.
在 Windows 上,Go Ticker 分辨率可能最多限制为一毫秒。
关于golang 在 1 秒内每 1 毫秒执行一次函数(每秒调用 1000 次),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50994524/