如何在 python 3.x 中创建给定列表的所有子集的列表?
给出的列表像 [1,2,3]
我想要一个像
[[1],[2],[3],[1,2],[2,3],[1,3],[1,2,3],[]]
最佳答案
您可以使用 itertools.combinations
获得组合:
>>> import itertools
>>> xs = [1, 2, 3]
>>> itertools.combinations(xs, 2) # returns an iterator
<itertools.combinations object at 0x7f88f838ff48>
>>> list(itertools.combinations(xs, 2)) # yields 2-length subsequences
[(1, 2), (1, 3), (2, 3)]
>>> for i in range(0, len(xs) + 1): # to get all lengths: 0 to 3
... for subset in itertools.combinations(xs, i):
... print(list(subset))
...
[]
[1]
[2]
[3]
[1, 2]
[1, 3]
[2, 3]
[1, 2, 3]
结合列表理解,你会得到你想要的:
>>> [list(subset) for i in range(0, len(xs) + 1)
for subset in itertools.combinations(xs, i)]
[[], [1], [2], [3], [1, 2], [1, 3], [2, 3], [1, 2, 3]]
关于python - 在 python 3.x 中创建给定列表的所有子集的列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43014681/