Python for 循环以不满足条件结束

Question

我有一个程序，它要求用户输入两个数字，并检查这两个数字之间的每个数字是否都可以被 5 和 7 整除。 如果范围内的数字不能被 5 和 7 除，我希望程序输出类似“找不到数字”的内容。 例如，如果用户输入 3 和 4，它将打印“No number found”

我尝试了几种不同的方法，但都没有用。

start = int(input("Start: "))
stop = int(input("Stop: "))


for number in range(start, (stop+1),1):
    if number % 5 == 0 and number % 7 ==0:
        print("Number", number, "can be divided with 5 and 7")
        print("Stop search")
        break
    elif  number % 5 == 0 and number % 7 !=0:
        print(number, "can't be divided with 7, next.")
    elif number % 5 != 0:
        print(number,"can't be divided with 5, next.")

Answer 1

您可以将 else: 子句与 for 循环一起使用。它仅在整个 for 循环正常结束并且没有到达 break 子句时执行。在极少数情况下它很有用!

for number in range(start, (stop+1),1):
    if number % 5 == 0 and number % 7 ==0:
        print("Number", number, "can be divided with 5 and 7")
        print("Stop search")
        break
    elif  number % 5 == 0 and number % 7 !=0:
        print(number, "can't be divided with 7, next.")
    elif number % 5 != 0:
        print(number,"can't be divided with 5, next.")
else:
    print("No number that can be divided by both 5 and 7 found.")