我正在创建一个网络抓取脚本并将其分为四个部分。分别地,它们都工作得很好,但是当我把它们放在一起时,我得到以下错误:urlopen error [Errno 111] Connection refused。我看过与我类似的问题,并尝试使用 try-except 来捕获错误,但即使那样也不起作用。我的多合一代码是:
from selenium import webdriver
import re
import urllib2
site = ""
def phone():
global site
site = "https://www." + site
if "spokeo" in site:
browser = webdriver.Firefox()
browser.get(site)
content = browser.page_source
browser.quit()
m_obj = re.search(r"(\(\d{3}\)\s\d{3}-\*{4})", content)
if m_obj:
print m_obj.group(0)
elif "addresses" in site:
usock = urllib2.urlopen(site)
data = usock.read()
usock.close()
m_obj = re.search(r"(\(\d{3}\)\s\d{3}-\d{4})", data)
if m_obj:
print m_obj.group(0)
else :
usock = urllib2.urlopen(site)
data = usock.read()
usock.close()
m_obj = re.search(r"(\d{3}-\s\d{3}-\d{4})", data)
if m_obj:
print m_obj.group(0)
def pipl():
global site
url = "https://pipl.com/search/?q=tom+jones&l=Phoenix%2C+AZ%2C+US&sloc=US|AZ|Phoenix&in=6"
usock = urllib2.urlopen(url)
data = usock.read()
usock.close()
r_list = [#re.compile("spokeo.com/[^\s]+"),
re.compile("addresses.com/[^\s]+"),
re.compile("10digits.us/[^\s]+")]
for r in r_list:
match = re.findall(r,data)
for site in match:
site = site[:-6]
print site
phone()
pipl()
这是我的回溯:
Traceback (most recent call last):
File "/home/lazarov/.spyder2/.temp.py", line 48, in <module>
pipl()
File "/home/lazarov/.spyder2/.temp.py", line 46, in pipl
phone()
File "/home/lazarov/.spyder2/.temp.py", line 25, in phone
usock = urllib2.urlopen(site)
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 400, in open
response = self._open(req, data)
File "/usr/lib/python2.7/urllib2.py", line 418, in _open
'_open', req)
File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 1215, in https_open
return self.do_open(httplib.HTTPSConnection, req)
File "/usr/lib/python2.7/urllib2.py", line 1177, in do_open
raise URLError(err)
urllib2.URLError: <urlopen error [Errno 111] Connection refused>
在手动调试代码后,我发现错误来自函数 phone(),所以我尝试只运行那一段:
import re
import urllib2
url = 'http://www.10digits.us/n/Tom_Jones/Phoenix_AZ/1fe293a0b7'
usock = urllib2.urlopen(url)
data = usock.read()
usock.close()
m_obj = re.search(r"(\d{3}-\d{3}-\d{4})", data)
if m_obj:
print m_obj.group(0)
它奏效了。我认为,这表明这并不是防火墙主动拒绝连接或相应服务未在其他站点上启动或过载。我们将不胜感激。
最佳答案
通常细节决定成败。
根据你的回溯...
File "/usr/lib/python2.7/urllib2.py", line 1215, in https_open
return self.do_open(httplib.HTTPSConnection, req)
和你的源代码...
site = "https://www." + site
...我可能假设在您的代码中您正在尝试访问 https://www.10digits.us/n/Tom_Jones/Phoenix_AZ/1fe293a0b7
而在您的测试中您正在连接到http://www.10digits.us/n/Tom_Jones/Phoenix_AZ/1fe293a0b7
。
尝试将 https
替换为 http
(至少对于 www.10digits.us
):可能是您要抓取的网站does not respond to the port 443 but only to the port 80 (你甚至可以用你的浏览器检查它)
关于python - 为什么连接被拒绝?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21081544/