用 Scrapy 蜘蛛抓取一些数据后:
class Test_Spider(Spider):
name = "test"
def start_requests(self):
for i in range(900,902,1):
........
yield item
我将数据传递给管道对象,使用 SQLAlchemy::将其写入 SQLite 表
class SQLlitePipeline(object):
def __init__(self):
_engine = create_engine("sqlite:///data.db")
_connection = _engine.connect()
_metadata = MetaData()
_stack_items = Table("table1", _metadata,
Column("id", Integer, primary_key=True),
Column("detail_url", Text),
_metadata.create_all(_engine)
self.connection = _connection
self.stack_items = _stack_items
def process_item(self, item, spider):
is_valid = True
我希望能够将表名设置为变量,而不是像现在这样硬编码“table1”
。如何做到这一点?
最佳答案
假设您通过命令行传递此参数(例如 -s table="table1"
),定义一个 from_crawler
方法。
@classmethod
def from_crawler(cls, crawler):
# Here, you get whatever value was passed through the "table" parameter
settings = crawler.settings
table = settings.get('table')
# Instantiate the pipeline with your table
return cls(table)
def __init__(self, table):
_engine = create_engine("sqlite:///data.db")
_connection = _engine.connect()
_metadata = MetaData()
_stack_items = Table(table, _metadata,
Column("id", Integer, primary_key=True),
Column("detail_url", Text),
_metadata.create_all(_engine)
self.connection = _connection
self.stack_items = _stack_items
关于python - 如何将参数传递给 scrapy 管道对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41043970/