python - 按列表中的值对字典键进行排序？

Question

我有一本字典和一个列表。键的值与列表的值匹配，我只是想找出如何根据列表中的值对字典中的值进行排序。

>>> l = [1, 2, 37, 32, 4, 3]
>>> d = {
    32: 'Megumi', 
    1: 'Ai',
    2: 'Risa',
    3: 'Eri', 
    4: 'Sayumi', 
    37: 'Mai'
}

我试过使用类似...的东西

>>> sorted(dict.keys(), key=list.index)

...但显然这只会按所需顺序返回键。

(应该在凌晨 3 点意识到 list 和 dict 是可怕的名字，我将它们更改为 l 和 d相应地。)

Answer 1

不要隐藏内置的 dict 和 list

>>> L = [1, 2, 37, 32, 4, 3]
>>> D = {
...     32: 'Megumi',
...     1: 'Ai',
...     2: 'Risa',
...     3: 'Eri',
...     4: 'Sayumi',
...     37: 'Mai'
... }

# Seems roundabout to use sorted here
# This causes an index error for keys in D that are not listed in L
>>> sorted(D.items(), key=lambda x:L.index(x[0]))
[(1, 'Ai'), (2, 'Risa'), (37, 'Mai'), (32, 'Megumi'), (4, 'Sayumi'), (3, 'Eri')]
>>>

# I think this is more direct than using sorted.
# This also ignores/skips keys in D that aren't listed in L
>>> [(i,D[i]) for i in L]
[(1, 'Ai'), (2, 'Risa'), (37, 'Mai'), (32, 'Megumi'), (4, 'Sayumi'), (3, 'Eri')]
>>>