我有一句话,比方说:
敏捷的棕色狐狸跳过懒惰的狗
我想创建一个函数,它接受 2 个参数、一个句子和一个要忽略的事物列表。它用相反的词返回那个句子,但是它应该忽略我在第二个参数中传递给它的东西。这是我目前拥有的:
def main(sentence, ignores):
return ' '.join(word[::-1] if word not in ignores else word for word in sentence.split())
但这只有在我像这样传递第二个列表时才有效:
print(main('The quick brown fox jumps over the lazy dog', ['quick', 'lazy']))
但是,我想传递这样的列表:
print(main('The quick brown fox jumps over the lazy dog', ['quick brown', 'lazy dog']))
预期结果:
ehT quick brown xof spmuj revo eht lazy dog
所以基本上第二个参数(列表)将包含应该忽略的句子部分。不只是一个单词。
我必须为此使用正则表达式吗?我试图避免它......
最佳答案
我是第一个建议避免使用正则表达式的人,但在这种情况下,不使用正则表达式的复杂性要大于使用它们所增加的复杂性:
import re
def main(sentence, ignores):
# Dedup and allow fast lookup for determining whether to reverse a component
ignores = frozenset(ignores)
# Make a pattern that will prefer matching the ignore phrases, but
# otherwise matches each space and non-space run (so nothing is dropped)
# Alternations match the first pattern by preference, so you'll match
# the ignores phrases if possible, and general space/non-space patterns
# otherwise
pat = r'|'.join(map(re.escape, ignores)) + r'|\S+|\s+'
# Returns the chopped up pieces (space and non-space runs, but ignore phrases stay together
parts = re.findall(pat, sentence)
# Reverse everything not found in ignores and then put it all back together
return ''.join(p if p in ignores else p[::-1] for p in parts)
关于python - 如何在 python 中反转句子的部分内容?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39359599/