我正在尝试覆盖 get_bundle_detail_data
class MyResourse(ModelResource):
foo = fields.CharField( attribute = 'modelA__variableOnModelA' )
def get_bundle_detail_data(self, bundle):
return bundle.obj.foo
class Meta:
resource_name='resource'
代码行 foo = fields.CharField( attribute = 'modelA__variableOnModelA' )
, 我正在设置变量 foo
关于资源MyResource
, 到 modelA
上的变量称为 variableOnModelA
.这很好用。
但我正在尝试制作 variableOnModelA
是 MyResource
的标识符, 这样我就可以做 /api/v1/resource/bar/
获取详细MyResource
使用变量 foo
设置为 bar
.
我遇到的问题是错误:Invalid resource lookup data provided (mismatched type).
这个错误是什么意思?
终极问题:我如何使用foo
作为 detail_uri_name
?
编辑 型号:
class AgoraUser(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE, primary_key=True, related_name='agora_user')
class Meta:
db_table = 'agora_users'
网址:
full_api = Api(api_name='full')
full_api.register(AgoraUserResourse())
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^', include(full_api.urls)),
url(r'^', include(min_api.urls)),
url(r'^search/', include('haystack.urls')),
url(r'^accounts/login/$', auth_views.login, {'template_name': 'login.html'}, name='login'),
]
实际资源:
class AgoraUserResourse_min(ModelResource):
username = fields.CharField(attribute = 'user__username' )
class Meta:
resource_name='user'
#detail_uri_name = 'user__username'
queryset = AgoraUser.objects.all()
allowed_methods = ['get', 'put', 'post']
authentication = AgoraAuthentication()
authorization = AgoraAuthorization()
def get_bundle_detail_data(self, bundle):
return bundle.obj.username
最佳答案
看起来您需要为您的资源覆盖 detail_uri_kwargs
。
我结束了这样的事情:
from tastypie import fields
from tastypie.resources import ModelResource
from tastypie.bundle import Bundle
from .models import AgoraUser
class AgoraUserResourse(ModelResource):
username = fields.CharField(attribute='user__username')
class Meta:
resource_name='user'
detail_uri_name = 'user__username'
queryset = AgoraUser.objects.all()
allowed_methods = ['get', 'put', 'post']
# authentication = AgoraAuthentication()
# authorization = AgoraAuthorization()
def detail_uri_kwargs(self, bundle_or_obj):
if isinstance(bundle_or_obj, Bundle):
bundle_or_obj = bundle_or_obj.obj
return {
'user__username': bundle_or_obj.user.username
}
def get_bundle_detail_data(self, bundle):
return bundle.obj.username
关于python - Tastypie 使用自定义 detail_uri_name,类型不匹配错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38669717/