python - 删除python中字典值中的重复项

Question

不好意思题目含糊不清，不好解释。

我有一本字典，其中每个值都是一个项目列表。我希望删除重复的项目，以便每个项目在列表中出现的次数最少(最好一次)。

考虑字典:

example_dictionary = {"weapon1":[1,2,3],"weapon2":[2,3],"weapon3":[2,3]}

'weapon2' 和 'weapon3' 具有相同的值，因此结果应该是:

result_dictionary = {"weapon1":[1],"weapon2":[3],"weapon3":[2]}

因为我不介意顺序，它也会导致:

result_dictionary = {"weapon1":[1],"weapon2":[2],"weapon3":[3]}

但当“别无选择”时，它应该保留该值。考虑这本新词典:

example_dictionary = {"weapon1":[1,2,3],"weapon2":[2,3],"weapon3":[2,3],"weapon4":[3]}

现在，由于它不能在不将键留空的情况下仅分配一次“2”或“3”，因此可能的输出是:

result_dictionary = {"weapon1":[1],"weapon2":[3],"weapon3":[2],"weapon4":[3]}

我可以将问题放宽到只有第一部分并进行管理，尽管我更喜欢两个部分一起解决

Answer 1

#!/usr/bin/env python3

example_dictionary = {"weapon1":[1,2,3],"weapon2":[2,3],"weapon3":[2,3]}

result = {}
used_values = []

def extract_semi_unique_value(my_list):
    for val in my_list:
        if val not in used_values:
            used_values.append(val)
            return val
    return my_list[0]

for key, value in example_dictionary.items():
    semi_unique_value = extract_semi_unique_value(value)
    result[key] = [semi_unique_value]

print(result)