首先我想说这是一项硬件作业,我只是对我面临的错误有疑问
我制作了一个带有插入函数的 vector 模板,该函数将 data_type 添加到动态数组的末尾。这是我目前拥有的。
// Insert the value at the specified index by moving the tail
// when Size = Capacity the Vector has to be reallocated first
// to accomate the new element
void Insert(const DATA_TYPE& value, int index){
// If the Capacity is not large enough then ...
// allocate large vector
if (Size >= Capacity){
// 0. Let's boost the capacity
Capacity += CAPACITY_BOOST;
// 1. Allocate new larger vector
DATA_TYPE* newData = new DATA_TYPE[Capacity];
// 2. Copy from old Data into the newData
for( int i=0; i< Size; i++)
newData[i] = Data[i];
// 3. Delete the old Data
delete[] Data;
// 4. Replace old Data-pointer with the newData pointer
Data = newData;
}
// Move the tail
for(int i=index; i<Size;i++){
Data[i+1] = Data[i];
}
// Insert
Data[index] = value;
Size++;
}
DATA_TYPE& operator[] (int index) const{
return *this[index];
}
注意:使用私有(private)变量:大小、容量、数据(存储动态数组) 我很确定我已经正确实现了 add 或 push_back 函数。问题是每当我尝试 cout 诸如“cout << a[1];”之类的东西时,我都会收到错误消息。
while compiling class template member function 'int &Vector<DATA_TYPE>::operator [](int) const'
with
[
DATA_TYPE=int
]
see reference to class template instantiation 'Vector<DATA_TYPE>' being compiled
with
[
DATA_TYPE=int
]
error C2440: 'return' : cannot convert from 'const Vector<DATA_TYPE>' to 'int &'
with
[
DATA_TYPE=int
]
最佳答案
operator[]
应该有两个版本:
const DATA_TYPE& operator[] (int index) const;
DATA_TYPE& operator[] (int index);
你所拥有的是两者的奇怪组合。
你也应该回来
return Data[index];
返回 (*this)[index];
会导致无限递归调用(好吧,不是无限,你会在这之前得到一个 stackoverflow)。
关于C++ vector 模板运算符 [],我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12803387/