这里绝对是初学者(第一篇文章),我刚刚完成一项任务,我必须创建一个程序,让用户创建员工工资单,然后通过按姓氏、名字、员工编号等进行搜索来显示它们。
我遇到了一个问题,如果我为 Nancy Davidson 创建记录,例如如果我完全搜索 Nancy 或 Davidson,我可以正确输出此记录。如果我搜索 nancy 或 davidson,它找不到。
我正在使用一个结构来存储每个员工的详细信息,将它们写入数据文件,然后读取该文件以显示记录。
有没有办法让我在搜索 NAncY 时仍然显示记录?
这是我按姓氏搜索功能的代码:
//Record search by employee SURNAME only
void searchSurname(Employee data[], int row)
{
string surname, again;
double wholeTot=0, wholeNet=0;
again = "y";
while (again=="y"||again=="Y")
{
row=0;
bool found = false;
clrscr();
cout << "Please enter Employee SURNAME : ";
Input(surname);
clrscr();
cout << "Surname Search results for " << surname << ". \n\n\n";
readFile (data, row);
int stop=row;
for ( row = 0; row < (stop) ; row++ )
if (surname == data[row].surname)
{
deconvertDate(data[row].date);
cout << " ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~" << endl
<< " # Employee Number - " << RIGHT(19,2) << data[row].empnum << " #" << endl
<< " # Employee Surname - " << RIGHT(18,2) << data[row].surname << " #" << endl
<< " # Employee Forename - " << RIGHT(17,2) << data[row].forename << " #" << endl
<< " # Department Number - " << RIGHT(17,2) << data[row].dept << " #" << endl
<< " # Normal Hours Worked - " << RIGHT(15,2) << data[row].hours << " #" << endl
<< " # Overtime Hours Worked - " << RIGHT(13,2) << data[row].ohours << " #" << endl
<< " # Pay Rate - " << RIGHT(26,2) << data[row].rate << " #" << endl
<< " # Gross Pay - " << RIGHT(25,2) << data[row].grosspay << " #" << endl
<< " # Tax - " << RIGHT(31,2) << data[row].tax << " #" << endl
<< " # National Insurance - " << RIGHT(16,2) << data[row].natin << " #" << endl
<< " # Total Deductions - " << RIGHT(18,2) << data[row].totalDeduct << " #" << endl
<< " # Net Pay - " << RIGHT(27,2) << data[row].net << " #" << endl
<< " # Week Ending - " << RIGHT(23,2) << data[row].date << " #" << endl
<< " ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~" << endl << endl << endl;
wholeTot+=data[row].grosspay;
wholeNet+=data[row].net;
cout << "The total recorded GROSS PAY of " << data[row].surname << " is :" << wholeTot << endl;
cout << " and the total recorded NET PAY is :" << wholeNet << endl << endl;
found = true;
}
else
if (found = false)
{
cout << "No results found for that SURNAME!" << endl;
}
最佳答案
当您调用 std::equal
时为了比较,你可以给它
与比较器的第四个参数。只写一个比较器
不区分大小写的比较:
struct CaseInsensitiveCmp
{
bool operator()( char lhs, char rhs ) const
{
return ::tolower( static_cast<unsigned char>( lhs ) )
== ::tolower( static_cast<unsigned char>( rhs ) );
}
};
(这在 tolower
中使用一个参数 <ctype.h>
函数,
这是初学者最简单的解决方案。生产中
代码,当然,你会使用 std::ctype
刻面
<locale>
.)
关于c++ - 接受用户输入无论他们在 C++ 中输入大写还是小写,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16442597/