c++ - 派生类中的 operator<< 可以在 C++ 的基类中调用另一个 operator<< 吗？

Question

在我的代码中，Manager源自 Employee他们每个人都有一个 operator<<覆盖。

class Employee{
protected:
    int salary;
    int rank;
public:
    int getSalary()const{return salary;}
    int getRank()const{return rank;}
    Employee(int s, int r):salary(s), rank(r){};
};
ostream& operator<< (ostream& out, Employee& e){
    out << "Salary: " << e.getSalary() << " Rank: " << e.getRank() << endl;
    return out;
}

class Manager: public Employee{
public:
    Manager(int s, int r): Employee(s, r){};
};
ostream& operator<< (ostream& out, Manager& m){   
    out << "Manager: ";
    cout << (Employee)m << endl;  //can not compile, how to call function of Employee?
    return out;
}

我希望cout << (Employee)m << endl;会调用ostream& operator<< (ostream& out, Employee& e) , 但它失败了。

Answer 1

转换为引用而不是拷贝:

cout << (Employee&)m << endl;  //can not compile, how to call function of Employee?

另请注意，ostream 运算符绝不是该类的成员(从问题的标题来看，您似乎对此感到困惑)。