c++ - 试图拒绝负数并让人们选择另一个但它完成了

Question

我试图在有人试图输入负数时出现“检测到无效数字。请输入正整数”，但编译器将其视为零，从而完成程序

#include <iostream>
using namespace std;

int main() {
    int number, minimum, maximum;

    cout << " Enter any positive integers \n";
    cout << " Enter zero when you want to stop \n";
    cin >> number;

    while (number < 0) {

        cout << "Invalid number detected. Please enter a positive integer. \n";
        cin >> number;
    }
    minimum = number;
    maximum = number;

    while (number > 0) {
        cout << " Enter any positive integers \n";
        cout << " Enter zero when you want to stop \n";
        cin >> number;

        if (number > maximum)
            maximum = number;

        if ((number < minimum) && (number != 0))
            minimum = number;
    }
    cout << " your minumum number is " << minimum << endl;
    cout << " your maximum is " << maximum << endl;

    system("pause");
    return 0;
}

Answer 1

我希望这对开始有所帮助。如果您需要在数字为 0 时停止，那么您需要检查它，而不是检查 < 0或 > 0

#include <iostream>
using namespace std;

int main()
{
    int number = -1;
    while(number != 0)
    {
        cout << "Enter any positive integers or enter 0 to stop: ";
        cin  >> number;
        if (number < 0)
            cout << "Invalid number detected, please insert positive number or 0 to stop: ";
    }

    return 0;
}

此外，我建议注意你的编码风格，你可以从Google coding style开始。