我正在做一些编程作业,我正在尝试使用for循环
来促进编码过程。这是循环:
#ifndef DIVSALES_H
#define DIVSALES_H
class DivSales
{
public:
DivSales(){ quarterSales[4] = {0}; };
double getTotalSales() { return totalSales;}
static void setTotalSales(double);
static void addTotalSales(double);
double getQuarterSales(int numQuarter) {return quarterSales[numQuarter];}
void setQuarterSales(int numQuarter, double numAmount) { quarterSales[numQuarter] = numAmount;}
private:
static double totalSales;
double quarterSales[];
};
double DivSales::totalSales = 0;
void DivSales::setTotalSales(double totalAmount) {totalSales = totalAmount; }
void DivSales::addTotalSales(double addAmount) {totalSales += addAmount; }
#endif // DIVSALES_H
#include <iostream>
#include "DivSales.h"
using namespace std;
int main()
{
const int NUMDIVS = 6;
const int NUMQUARTERS = 4;
double amount = 0;
DivSales divs[NUMDIVS];
for(int division = 0; division < NUMDIVS; division++)
{
cout << "Division " << (division + 1) << endl;
for(int quarter = 0; quarter < NUMQUARTERS; quarter++)
{
cout << "Quarter " << (quarter + 1) << ": ";
cin >> amount;
divs[division].setQuarterSales(quarter, amount);
DivSales::addTotalSales(amount);
}
}
return 0;
}
输出示例:
Division 1
Quarter 1: 500
Quarter 2: 500
Quarter 3: 500
Quarter 2: 500
Quarter 3: 500
Quarter 2: 500
Quarter 3: 500
Quarter 2: 500
Quarter 3: 500
Quarter 2:
我想做的是,当我输入一个分区的 4 个季度的数字时,它将移动到下一个分区。然而,在 4 个输入之后,它不会递增 for 循环的除法变量,而是继续请求更多输入。这是怎么回事?
最佳答案
我已经找到了导致该问题的原因,它位于文件 DivSales.h 中:
更改此行:
double quarterSales[];
对于这一行:
double quarterSales[4];
问题是您没有为 4 个元素的数组分配内存。要初始化它,请将构造函数更改为:
DivSales():quarterSales({0}){ };
您还应该将以下行移动到 DivSales.cpp,否则我会收到多重定义错误:
double DivSales::totalSales = 0;
关于c++ - 嵌套 For 循环 (C++) 无法正常工作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19593749/