go - 使用 channel 同步多个 goroutine

Question

我需要启动一些具有单一任务队列和单一结果队列的工作人员。每个 worker 应该在不同的 goroutine 中启动。而且我需要等到所有工作人员都完成并且任务队列为空才能退出程序。 我已经为 goroutine 同步准备了一个小例子。 主要思想是我们计算队列中的任务并等待所有工作人员完成工作。但目前的实现有时会错过值(value)。 为什么会发生这种情况以及如何解决问题？ 示例代码:

import (
    "fmt"
    "os"
    "os/signal"
    "strconv"
)

const num_workers = 5

type workerChannel chan uint64

// Make channel for tasks
var workCh workerChannel
// Make channel for task counter
var cntChannel chan int

// Task counter
var tskCnt int64

// Worker function
func InitWorker(input workerChannel, result chan string, num int) {
    for {
        select {
        case inp := <-input:
            getTask()
            result <- ("Worker " + strconv.Itoa(num) + ":" + strconv.FormatUint(inp, 10))
        }
    }
}

// Function to manage task counter
// should be in uniq goroutine
func taskCounter(inp chan int) {
    for {
        val := <-inp
        tskCnt += int64(val)
    }
}

// Put pask to the queue
func putTask(val uint64) {
    func() {
        fmt.Println("Put ", val)
        cntChannel <- int(1)
        workCh <- val
    }()
}

// Get task from queue
func getTask() {
    func() {
        cntChannel <- int(-1)
    }()
}

func main() {
// Init service channels
    abort := make(chan os.Signal)
    done := make(chan bool)

// init queue for results
    result := make(chan string)

// init task queue
    workCh = make(workerChannel)

// start some workers
    for i := uint(0); i < num_workers; i++ {
        go InitWorker(workCh, result, int(i))
    }

// init counter for synchro
    cntChannel = make(chan int)
    go taskCounter(cntChannel)

// goroutine that put some tasks into queue
    go func() {
        for i := uint(0); i < 21; i++ {
            putTask(uint64(i))
        }

        // wait for processing all tasks and close application
        for len(cntChannel) != 0 {}
        for tskCnt != 0 {}
        for len(workCh) != 0 {}
        for len(result) != 0 {}

        // send signal for close
        done <- true
    }()

    signal.Notify(abort, os.Interrupt)
    for {
        select {
        case <-abort:
            fmt.Println("Aborted.")
            os.Exit(0)

        // print results
        case res := <-result:
            fmt.Println(res)

        case <-done:
            fmt.Println("Done")
            os.Exit(0)
        }
    }
}

Answer 1

使用sync.WaitGroup等待 goroutines 完成。关闭 channel 以导致 channel 上的循环读取退出。

package main

import (
    "fmt"
    "sync"
)

type workerChannel chan uint64

const num_workers = 5

func main() {

    results := make(chan string)
    workCh := make(workerChannel)

    // Start workers
    var wg sync.WaitGroup
    wg.Add(num_workers)
    for i := 0; i < num_workers; i++ {
        go func(num int) {
            defer wg.Done()
            // Loop processing work until workCh is closed
            for w := range workCh {
                results <- fmt.Sprintf("worker %d, task %d", num, w)
            }

        }(i)
    }

    // Close result channel when workers are done
    go func() {
        wg.Wait()
        close(results)
    }()

    // Send work to be done
    go func() {
        for i := 0; i < 21; i++ {
            workCh <- uint64(i)
        }
        // Closing the channel causes workers to break out of loop
        close(workCh)
    }()

    // Process results. Loop exits when result channel is closed.
    for r := range results {
        fmt.Println(r)
    }
}

https://play.golang.org/p/ZifpzsP6fNv