python - 当用户输入相同的输入两次(预期)时，如何将输入组合到输出？

Question

我的测试代码适用于输入一天的第一条记录，但代码主体不起作用。该代码继续运行，询问工作的日期和时间。我输入“完成”，它也不接受。

我最初想为输入的日期创建一个列表，但不确定在进入下一个输入之前何时访问该列表以打印页脚。没有错误只是不会按预期执行。这是一项任务，许多声明已经填充。

用户输入的预期结果:

工作日:星期二 工作时间:3 工作日:周二 工作时间:4 第 7 天

这是我的代码。

HEAD1 = "WEEKLY HOURS WORKED"
DAY_FOOTER = "Day Total "
SENTINEL = "done"   # Named constant for sentinel value
hoursWorked = 0     # Current record hours
hoursTotal = 0      # Hours total for a day
prevDay = ""        # Previous day of week
notDone = True      # loop control
days=[]



# Print two blank lines.
print("\n\n")
# Print heading.
print("\t" + HEAD1)
# Print two blank lines.
print("\n\n")

# Read first record 
dayOfWeek = input("Enter day of week or done to quit: ")
if dayOfWeek  == SENTINEL:
    notDone = False

else:
    hoursWorked =int(input("Enter hours worked: "))
    prevDay = dayOfWeek
    hoursTotal = hoursWorked
    days.append(dayOfWeek)
    print("\t" + DAY_FOOTER + str(hoursTotal))
    print(days)

while notDone == True:
    dayOfWeek = input("Enter day of week or done to quit: ")
    prevDay = dayOfWeek
    hoursWorked =int(input("Enter hours worked: "))
    hoursTotal = 0
    hoursTotal = hoursTotal + hoursWorked
    days.append(dayOfWeek)
    print(days)

    def dayChange(DAY_FOOTER,hoursWorked):
        if dayOfWeek == dayOfWeek:
            DAY_FOOTER = dayOfWeek
            hoursTotal = (hoursWorked + hoursWorked)
            print("\t" + DAY_FOOTER + str(hoursTotal))
            days.append(dayOfWeek)


        else:
            print("\t" + DAY_FOOTER + str(hoursTotal))

def endOfProgram(done):
    if dayOfWeek == "done":
        notDone == False
        return```

Answer 1

代码有几个问题:

首先，您对 while 循环中的“done”命令并不是很敏感。您确实测试了 notDone 变量，但您从不在循环内写入该变量。测试应该嵌入循环本身，在循环之外是多余的。其次，在 while 循环的每次迭代中，您都将 hoursTotal 变量初始化为 0，这样您就不会记住前几天的值。也许您应该使用一个额外的列表来跟踪小时数，或者使用 day_of_the_week:hours 字典。