我是 C++ 新手。我的背景来自 PHP 和 C#。我在 Visual Studio 2005 中用 VC++ 实现二叉搜索树
所有操作都很好,我在一种特定情况下遇到删除问题,即当我尝试删除 head 两次或更多次时。
建议的策略是
- Find minimum in the right sub tree
- Replace the node you want to delete with minimum
- delete minimum
在我的代码中 8 在顶部,当我第一次删除顶部时,比 11 从右子树成为顶部,如果我删除任何其他节点,代码工作正常,但如果我再次删除顶部(删除后8 现在是 11) 我得到以下错误
Windows has triggered a breakpoint in BinarySearchTreeByList.exe.
This may be due to a corruption of the heap, and indicates a bug in >BinarySearchTreeByList.exe or any of the DLLs it has loaded.
The output window may have more diagnostic information
完整代码如下
#include "stdafx.h"
#include <stdio.h>
#include <tchar.h>
#include <list>
#include <iostream>
typedef struct node
{
node* left;
node* right;
node* parent;
int val;
};
using namespace std;
void insert_node(node** iterate, int newVal, node* newParent);
void traverse(node* iterate);
void del(node** iterate, int newVal, char direction);
void traverse(node* iterate)
{
if(iterate != NULL)
{
traverse(iterate->left);
printf("%d ",iterate->val);
traverse(iterate->right);
}
}
void del(node** iterate, int newVal, char direction)
{
if((*iterate) == NULL)
return;
if((*iterate)->val == newVal)
{
if((*iterate)->left == NULL && (*iterate)->right == NULL)
{
if(direction == 't')
{
node* deleted = *iterate;
*iterate = NULL;
free(deleted);
}
if(direction == 'l')
{
node* deleted = (*iterate)->parent->left;
(*iterate)->parent->left = NULL;
free(deleted);
}
if(direction == 'r')
{
node* deleted = (*iterate)->parent->right;
(*iterate)->parent->right = NULL;
free(deleted);
}
return;
}
if((*iterate)->left == NULL)
{
if(direction == 't')
{
node* deleted = *iterate;
*iterate = (*iterate)->right;
(*iterate)->parent = NULL;
free(deleted);
}
if(direction == 'l')
{
node* deleted = *iterate;
(*iterate)->parent->left = (*iterate)->right;
free(deleted);
}
if(direction == 'r')
{
node* deleted = *iterate;
(*iterate)->parent->right = (*iterate)->right;
free(deleted);
}
return;
}
if((*iterate)->right == NULL)
{
if(direction == 't')
{
node* deleted = *iterate;
*iterate = (*iterate)->left;
(*iterate)->parent = NULL;
free(deleted);
}
if(direction == 'l')
{
node* deleted = *iterate;
(*iterate)->parent->left = (*iterate)->left;
free(deleted);
}
if(direction == 'r')
{
node* deleted = *iterate;
(*iterate)->parent->right = (*iterate)->left;
free(deleted);
}
return;
}
node* findmin = (*iterate)->right;
int minVal = 0;
while(findmin != NULL)
{
minVal = findmin->val;
findmin = findmin->left;
}
(*iterate)->val = minVal;
del(&((*iterate)->right), minVal, 'r');
return;
}
if(newVal < (*iterate)->val)
del(&((*iterate)->left) ,newVal, 'l');
else
del(&((*iterate)->right) ,newVal, 'r');
}
void insert_node(node** iterate, int newVal, node* newParent)
{
if(*iterate == NULL)
{
node* newNode = (node*)malloc(sizeof(node));
newNode->val = newVal;
newNode->left = NULL;
newNode->right = NULL;
newNode->parent = newParent;
*iterate = newNode;
return;
}
if(newVal < (*iterate)->val)
insert_node(&((*iterate)->left) , newVal, *iterate);
else
insert_node(&((*iterate)->right) , newVal, *iterate);
}
int main()
{
node* iterate = NULL;
insert_node(&iterate, 8, NULL);
insert_node(&iterate, 15, NULL);
insert_node(&iterate, 4, NULL);
insert_node(&iterate, 2, NULL);
insert_node(&iterate, 1, NULL);
insert_node(&iterate, 3, NULL);
insert_node(&iterate, 7, NULL);
insert_node(&iterate, 6, NULL);
insert_node(&iterate, 11, NULL);
insert_node(&iterate, 22, NULL);
insert_node(&iterate, 12, NULL);
insert_node(&iterate, 13, NULL);
traverse(iterate);
printf("\n\n");
del(&iterate, 8, 't');
del(&iterate, 22, 't');
del(&iterate, 7, 't');
del(&iterate, 11, 't');
printf("\n\n");
traverse(iterate);
cin.clear();
cin.ignore(255, '\n');
cin.get();
}
谢谢你的帮助
最佳答案
您的问题是,当您删除一个节点时,您将已删除父节点的子节点指针设置为已删除节点的子节点,但您没有将已删除父节点的子节点指针设置为已删除节点的子节点。
例如:
if(direction == 'l')
{
node* deleted = *iterate;
(*iterate)->parent->left = (*iterate)->right;
deleted->right->parent = deleted->parent;
free(deleted);
}
你错过了 deleted->right->parent = deleted->parent;
行,我添加了它。
您应该以相同的方式修复代码中的其他几个地方。
关于C++二叉搜索树删除问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21108143/