c++ - 使用带有多个参数的 scanf

Question

cout<<"\n\t Please input the real and the complex part respectively :";
if(scanf("%d+i%d",&real_part,&complex_part)!=2)
{   
    if(real_part>0)
        cout<<"\n\t You have entered only the real part";
}

这里我想扫描一个复数。为此，上面的代码工作正常。如果我们输入单个数字，它被分配为实部。但我想如果我只给出 i4 作为它将分配给 complex_part 的输入保持实部不变(我已经初始化了两个变量)。有什么办法可以实现吗？？

Answer 1

这就足够了:

if(scanf("%d", &real_part) == 1) /* If scanf succeeded in reading the real part */
{
    if(scanf("+i%d", &complex_part) == 1) /* If scanf succeeded in reading the imaginary part */
    {
        printf("Real part=%d, complex part=%d\n", real_part, complex_part);
    }
    else
    {
        printf("Real part=%d, complex part=%d\n", real_part, 0);
    }
}
else if(scanf("i%d", &complex_part) == 1) /* If scanf succeeded in reading the imaginary part */
{
        printf("Real part=%d, complex part=%d\n", 0, complex_part);
}