我有一组传入记录,需要根据定义和存储的一组逻辑子句进行评估。一个示例逻辑子句如下:
Acct1 != 'Y' AND Acct2 > 1004 AND Acct3 >= 96 AND Acct4 < 1004 AND Acct5 = 99 AND ((Acct6 <= 9090 OR Acct7 IN (A1,A2,A6) AND Acct1 NOT IN (A3,A4)) AND Formatted LIKE 'LINUX' AND Acct9 NOT LIKE 'WINDOWS' AND (Acct10 = 'N' AND NOT Acct11 = 'N') AND EditableField BETWEEN (10 AND 20) )
我对子句的数据输入如下:
map.put(Acct1,"Y")
map.put(Acct2,1010)
map.put(Acct3,99)
map.put(Acct4,1015)
map.put(Acct5,99)
map.put(Acct6,9090)
map.put(Acct7,"A3")
map.put(Formatted,"LINUX_INST")
map.put(Updated,"LINUX_TMP")
map.put(Acct10,"Y")
map.put(Acct11,"N")
map.put(EditableFIeld,25)
我必须根据上面定义的子句评估填充到映射中的传入记录,并根据评估结果打印真或假。
子句条件和映射值也将被更改和执行。
我要评估以下条件子句:
!=
>
>=
<
=
<=
IN(
NOT IN(
LIKE(
NOT LIKE(
BETWEEN(
AND
OR
AND NOT
OR NOT
我尝试过使用语法生成器,但有人告诉我这不是我们应用程序的推荐解决方案,因此我正在寻找 Java 代码,并且我有这个详细的示例供引用 AND、OR、=。 resolving logical operations - AND, OR, looping conditions dynamically并在可能的情况下寻找在此基础上构建的片段。
最佳答案
如果您想避免解析器生成器,请考虑使用 StreamTokenizer 来实现递归下降解析器,每个语法规则都有一个方法。
对于你的语法的一个子集,这应该看起来大致像这样(并且应该很容易扩展到你的完整语法):
public class Parser {
public static Node parse(String expr) {
StreamTokenizer tokenizer =
new StreamTokenizer(new StringReader(expr));
tokenizer.nextToken();
Parser parser = new Parser(tokenizer);
Node result = parser.parseExpression();
if (tokenizer.ttype != StreamTokenizer.TT_EOF) {
throw new RuntimeException("EOF expected, got "
+ tokenizer.ttype + "/" + tokenizer.sval);
}
private StreamTokenizer tokenizer;
private Parser(StreamTokenizer tokenizer) {
this.tokenizer = tokenizer;
}
private Node parseExpression() {
Node left = parseAnd();
if (tokenizer.ttype == StreamTokenizer.TT_WORD
&& tokenizer.sval.equals("OR")) {
tokenizer.nextToken();
return new OperationNode(OperationNode.Type.OR,
left, parseExpression());
}
return left;
}
private Node parseAnd() {
Node left = parseRelational();
if (tokenizer.ttype == StreamTokenizer.TT_WORD
&& tokenizer.sval.equals("AND")) {
tokenizer.nextToken();
return new OperationNode(OperationNode.Type.AND,
left, parseAnd());
}
return left;
}
private Node parseRelational() {
Node left = parsePrimary();
OperationNode.Type type;
switch (tokenizer.ttype) {
case '<': type = OperationNode.Type.LESS; break;
case '=': type = OperationNode.Type.EQUAL; break;
case '>': type = OperationNode.Type.GREATER; break;
default:
return left;
}
tokenizer.nextToken();
return new OperationNode(type, left, parseRelational());
}
private Node parsePrimary() {
Node result;
if (tokenizer.ttype == '(') {
tokenizer.nextToken();
result = parseExpression();
if (tokenizer.ttype != ')') {
throw new RuntimeException(") expected, got "
+ tokenizer.ttype + "/" + tokenizer.sval);
}
} else if (tokenizer.ttype == '"' || tokenizer.ttype == '\'') {
result = new LiteralNode(tokenizer.sval);
} else if (tokenizer.ttype == TT_NUMBER) {
result = new LiteralNode(tokenizer.nval);
} else if (tokenizer.ttype == StreamTokenizer.TT_WORD) {
result = new FieldNode(tokenizer.sval);
} else {
throw new RuntimeException("Unrecognized token: "
+ tokenizer.ttype + "/" + tokenizer.sval);
}
tokenizer.nextToken();
return result;
}
}
这假定了一个像这样的 Node 对象层次结构:
interface Node {
Object eval(Map<String,Object> data);
}
class FieldNode implements Node {
private String name;
FieldNode(String name) {
this.name = name;
}
public Object eval(Map<String,Object> data) {
return data.get(name);
}
}
class LiteralNode implements Node {
private Object value;
FieldNode(Object value) {
this.value = value;
}
public Object eval(Map<String,Object> data) {
return value;
}
}
class OperationNode implements Node {
enum Type {
AND, OR, LESS, GREATER, EQUALS
}
private Type type;
private Node leftChild;
private Node rightChild;
OperationNode(Type type, Node leftChild, Node rightChild) {
this.type = type;
this.leftChild = leftChild;
this.rightChild = rightChild;
}
public Object eval(Map<String,Object> data) {
Object left = leftChild.eval(data);
Object right = rightChild.eval(data);
switch (type) {
case AND: return ((Boolean) left) && ((Boolean) right);
case OR: return ((Boolean) left) || ((Boolean) right);
case LESS: return ((Comparable) left).compareTo(right) < 0;
case EQUALS: return left.equals(right);
case GREATE: return ((Comparable) left).compareTo(right) > 0;
default:
throw new RuntimeException("Invalid op: " + type);
}
}
关于java复杂逻辑条件解析器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32726833/