我有一组具有父子关系的自定义节点。每个节点可以是复合类型(其中有其他子节点)或简单类型(叶级节点)
我想写一个函数来给我所有死节点的列表。 例如这里是节点集合
基于上述情况,p2、p3、p8、p9、p10、p6、c1 是死节点(因为在它们的层次结构中没有任何简单节点)
我需要一个函数作为
private List<NodeEntity> GetDeadNodes(List<NodeEntity> originalList)
这是拥有原始列表的函数
private List<NodeEntity> GetOriginalList()
{
var list = new List<NodeEntity>()
{
new NodeEntity() {Code = "P1", ParentCode = "001", Type = NodeType.Composite},
new NodeEntity() {Code = "C1", ParentCode = "001", Type = NodeType.Composite},
new NodeEntity() {Code = "P2", ParentCode = "P1", Type = NodeType.Composite},
new NodeEntity() {Code = "P3", ParentCode = "P2", Type = NodeType.Composite},
new NodeEntity() {Code = "P8", ParentCode = "P3", Type = NodeType.Composite},
new NodeEntity() {Code = "P9", ParentCode = "P3", Type = NodeType.Composite},
new NodeEntity() {Code = "P4", ParentCode = "P1", Type = NodeType.Composite},
new NodeEntity() {Code = "L3", ParentCode = "P1", Type = NodeType.Simple},
new NodeEntity() {Code = "P6", ParentCode = "P1", Type = NodeType.Composite},
new NodeEntity() {Code = "P10", ParentCode = "P4", Type = NodeType.Composite},
new NodeEntity() {Code = "L2", ParentCode = "P4", Type = NodeType.Simple},
new NodeEntity() {Code = "P5", ParentCode = "P4", Type = NodeType.Composite},
new NodeEntity() {Code = "L1", ParentCode = "P5", Type = NodeType.Simple}
};
return list;
}
最佳答案
您可以从每个简单节点向上执行简单扫描,以收集要保留的所有节点(伪代码):
put Simple nodes in a Set
while node in Set
add node to a 'seen' list
add parent to Set
dead nodes = all nodes except 'seen' nodes
关于c# - 从父子节点集合中查找死节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45801336/