我希望将我的 routes.go 分成多个文件,以便每个组都在自己的包中。有人可以指出一些代码示例,其中有人使用 Gin 完成了此操作吗?
即
package auth
...
auth = route.Group("/auth"){
auth.GET(...
auth.POST(...
}
...
package users
...
user = route.Group("/user"){
user.GET(...
user.POST(...
}
...
package main
import (
"auth"
"users"
)
...
router = gin.Default()
router.Register(auth.auth, users.user)
router.Run()
...
最佳答案
这样做的方法是在每个函数中创建一个函数,将路由作为参数,然后将路由添加到参数中:
package auth
import "...gin"
func Routes(route *gin.Engine)
auth := route.Group("/auth"){
auth.GET(...
auth.POST(...
}
...
package users
import "...gin"
func Routes(route *gin.Engine)
user := route.Group("/user"){
user.GET(...
user.POST(...
}
...
package main
import (
"github.com/username/package/sub/auth"
"github.com/username/package/sub/users"
"github.com/gin-gonic/gin"
)
...
router := gin.Default()
auth.Routes(router) //Added all auth routes
user.Routes(router) //Added all user routes
router.Run()
...
关于Golang Gin-Gonic 将路由拆分成多个文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42967235/