我有一个订单表,其中包含客户 ID 和订单金额。我想加入这些订单,但加入的订单不能超过一定数量。下面是一个例子:
假设最大数量是 33 个托盘,我有一个这样的表:
Order ID Client ID Amount
1 100001 10
2 100001 22
3 100001 13
4 100001 33
5 100001 1
6 100001 5
7 100001 6
结果应该是:
Order ID Client ID Amount Joined ID Joined Amount
1 100001 10 100001A 32
2 100001 22 100001A 32
3 100001 13 100001B 13
4 100001 33 100001C 33
5 100001 1 100001D 12
6 100001 5 100001D 12
7 100001 6 100001D 12
这里,如果我们也能想出一种方法,将编号为5、6、7的订单加入到订单10001B中,那就太好了。但即使是这个解决方案也足够了。
我对如何解决这个问题有一些想法,但我无法真正想出一个可行的解决方案。我将像这样处理大约 2000 个订单 ID,所以我也不希望这是一个缓慢的操作。我正在使用 SQL Server 2014
最佳答案
您可以在这里借助递归 CTE 找到建议的解决方案(sql 定义):http://sqlfiddle.com/#!6/285c16/45
基本上 CTE 迭代有序列表(按 clientID、orderID)并评估总金额是否不超过 33。
我已将下一个 clientID 添加到模拟数据,以测试正确的子计数标准评估。
这里是获取结果的查询:
-- prepare numbering for iteration
with orders_nr
as
(
select row_number() over(order by clientID, id) as [nr],
o.*
from orders o
)
,
-- prepare sum totals
re
as
(
select id, amount, amount as amount_total ,o.[nr] as nr,
clientID
from orders_nr o
where o.[nr]=1
UNION ALL
select o.id, o.amount,
CASE WHEN o.clientID <> r.clientID then o.amount
ELSE o.amount+ r.amount_total END,
o.[nr] as nr, o.clientID
from orders_nr o join re r
on (o.[nr]=r.[nr]+1)
)
,
-- iterate total - evaluate current criteria (<=33)
re2 as
(
select re.id, re.amount, re.amount_total,
re.[nr] as [group], re.[nr], re.clientID
from re
where re.[nr]=1
UNION ALL
select r.id, r.amount,
CASE WHEN r.amount+re2.amount_total >33
OR r.clientID<>re2.clientID
then r.amount ELSE re2.amount_total+r.amount END
as amount_total,
CASE WHEN r.amount+re2.amount_total >33
OR r.clientID<>re2.clientID THEN
r.[nr] ELSE re2.[group] END as [group], r.[nr], r.clientID
from re r join re2
on (r.[nr]=re2.[nr]+1 )
)
, group_total
AS
(
select [group], clientID, max(amount_total) as total
FROM re2
group by [group], clientID
),
result
as
(
select
r.id, r.clientID, r.amount,
cast(r.clientid as varchar(20))
+'-'+char(64+cast(
dense_rank()
over( partition by r.clientID
order by r.[clientID], r.[group])
as varchar(3))) as joinedID
, gt.total as joinedAmount
from re2 as r join group_total gt
on (r.clientID=gt.clientID AND r.[group]=gt.[group])
)
select * from result
关于SQL 按一定数量分组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29265418/