javascript - 我如何计算数组的模式并忽略数据

Question

我正在尝试计算我可以执行的数组的模式，但我想排除 0

这是我的代码:

常量数据 = [0, 0, 0, 4, 4, 2, 3, 2, 0];

function mode(numbers) {
  var modes = [],
    count = [],
    i,
    number,
    maxIndex = 0;

  for (i = 0; i < numbers.length; i += 1) {
    number = numbers[i];
    count[number] = (count[number] || 0) + 1;
    if (count[number] > maxIndex) {
      maxIndex = count[number];
    }
  }

  for (i in count)
    if (count.hasOwnProperty(i)) {
      if (count[i] === maxIndex) {
        modes.push(Number(i));
      }
    }

  return modes;
}

mode(datas); // output : [0] and I want [4] [2]

感谢您抽出时间。

Answer 1

您可以简单地filter出零:

datas = [0, 0, 0, 4, 4, 2, 3, 2, 0];

function mode(numbers) {
  // we don't want to consider zeros
  // so filter them out
  numbers = numbers.filter(function(n) { return n !== 0 }); 

  var modes = [],
    count = [],
    i, number, maxIndex = 0;

  for (i = 0; i < numbers.length; i += 1) {
    number = numbers[i];
    count[number] = (count[number] || 0) + 1;
    if (count[number] > maxIndex) {
      maxIndex = count[number];
    }
  }

  for (i in count)
    if (count.hasOwnProperty(i)) {
      if (count[i] === maxIndex) {
        modes.push(Number(i));
      }
    }

  return modes;
}

console.log(mode(datas)) // output : [4] [2]

如果您使用的是 ES6，则可以使用箭头函数语法:

numbers = numbers.filter(n => n !== 0);