我需要存储锦标赛的数据。我需要知道有多少支球队将参加比赛(n)以及他们将参加的比赛数量(n!)。然后是球队的名字和成绩。像这样的事情:
Input:
3 6
TeamX
TeamY
TeamZ
TeamX 0 - TeamY 3
TeamX 1 - TeamZ 0
TeamY 1 - TeamX 0
TeamY 0 - TeamZ 0
TeamZ 0 - TeamX 0
TeamZ 3 - TeamY 1
输出将类似于:
This winner is TeamY, with 7 point(s)
Won 2 game(s), tied 1 game(s) e lost 1 game(s)
Scored 5 goal(s) e suffered 3 goal(s)
编辑2: 这就是我到目前为止所拥有的。但它在 scanf 上不起作用......我无法在球队数量和比赛数量后输入球队名称。你能运行它并尝试理解吗?
指南:我有游戏和团队结构,首先我将团队名称添加到结构的 Teams 数组中,然后将游戏添加到结构的 games 数组中。然后,if/else block 对胜利、失败等进行数学计算,最后查看并打印获胜者。
#include <stdio.h>
#include <string.h>
struct game {
const char *teamA;
int scoreA;
const char *teamB;
int scoreB;
};
struct team {
const char *teamA;
int score;
int wins;
int losses;
int ties;
int scored;
int suff;
};
struct team team_new(const char *teamA, int score, int wins, int losses, int ties, int scored, int suff)
{
struct team t;
t.teamA = strdup(teamA);
t.score = score;
t.wins = wins;
t.losses = losses;
t.ties = ties;
t.scored = scored;
t.suff = suff;
return t;
};
struct game game_new(const char *teamA, int scoreA, const char *teamB, int scoreB)
{
struct game g;
g.teamA = strdup(teamA);
g.scoreA = scoreA;
g.teamB = strdup(teamB);
g.scoreB = scoreB;
return g;
};
int main(void)
{
int i, j, teams, nrgames, biggestScore, whichTeam;
scanf("Teams and number of games %d %d", &teams, &nrgames);
//add team names to theTeamss struct
struct team theTeams[teams];
size_t num_teams = 0;
for (i = 0; i < teams; ++i)
{
char teamA[20];
if (scanf("%s", teamA) != 1)
exit(0);
theTeams[++num_teams] = team_new(teamA, 0, 0, 0, 0, 0, 0);
}
struct game games[nrgames]; //add games
size_t num_games = 0;
for (i = 0; i < sizeof games / sizeof *games; ++i)
{
char teamA[20], teamB[20];
int scoreA, scoreB;
if (scanf(" %s %d - %s %d", teamA, &scoreA, teamB, &scoreB) != 4)
exit(0);
games[++num_games] = game_new(teamA, scoreA, teamB, scoreB);
}
//run through games[] to change values of theTeams[] scores
//games - A against B
for (i = 0; i < sizeof games / sizeof *games; ++i)
{
for (j = 0; j < sizeof theTeams / sizeof *theTeams; ++j)
{
if ((games[i].teamA == theTeams[j].teamA)) //team(A)
{
//if A wins
if(games[i].scoreA > games[i].scoreB)
{
theTeams[j].score += 3;
theTeams[j].wins += 1;
theTeams[j].scored = games[i].scoreA;
}
//if A loses
else if (games[i].scoreA < games[i].scoreB)
{
theTeams[j].score += 0;
theTeams[j].losses += 1;
theTeams[j].suff = games[i].scoreB;
}
else //tied
{
theTeams[j].score += 1;
theTeams[j].ties += 1;
theTeams[j].suff = games[i].scoreA;
}
}
if ((games[i].teamB == theTeams[j].teamA))//team(B)
{
//if B wins
if(games[i].scoreB > games[i].scoreA)
{
theTeams[j].score += 3;
theTeams[j].wins += 1;
theTeams[j].scored = games[i].scoreB;
}
//if B loses
else if (games[i].scoreB < games[i].scoreA)
{
theTeams[j].score += 0;
theTeams[j].losses += 1;
theTeams[j].suff = games[i].scoreA;
}
else //tied
{
theTeams[j].score += 1;
theTeams[j].ties += 1;
theTeams[j].suff = games[i].scoreB;
}
}
}
}
//accessing to the winner team
biggestScore = theTeams[0].score;
whichTeam = 0;
for (i = 0; i < sizeof theTeams / sizeof *theTeams; ++i){
if (theTeams[i].score > biggestScore){
biggestScore = theTeams[i].score;
whichTeam = i;
}
}
//output
printf("\n This winner is %s, with %d point(s), Won %d game(s), tied %d game(s) and lost %d game(s), Scored %d goal(s) e suffered %d goal(s)\n", theTeams[whichTeam].teamA, theTeams[whichTeam].score, theTeams[whichTeam].wins, theTeams[whichTeam].losses, theTeams[whichTeam].ties, theTeams[whichTeam].scored, theTeams[whichTeam].suff);
return 0;
}
最佳答案
C语言和字符串没有“问题”;你想做什么,就可以做什么。与其他语言相比,它只是多了一点责任。
你似乎需要一个结构数组,是的。我建议将其建模为一系列所玩的游戏,其中每场游戏都会记录参加的团队及其得分。无需首先记录“可用”球队的列表,之后从游戏数据中提取该列表会更容易。
struct game {
const char *teamA;
int scoreA;
const char *teamB;
int scoreB;
};
struct game game_new(const char *teamA, int scoreA, const char *teamB, int scoreB)
{
struct game g;
g.teamA = strdup(teamA);
g.scoreA = scoreA;
g.teamB = strdup(teamB);
g.scoreB = scoreB;
return g;
}
然后在 man 程序中:
int main(void)
{
struct game games[100];
size_t num_games = 0;
for (size_t i = 0; i < sizeof games / sizeof *games; ++i)
{
char teamA[100], teamB[100];
int scoreA, scoreB;
if (scanf(" %s %d - %s %d", teamA, &scoreA, teamB, &scoreB) != 4)
break;
games[++num_games] = game_new(teamA, scoreA, teamB, scoreB);
}
}
关于c - C语言算法——谁是获胜队,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54982642/