我编写了以下合并排序代码。
public class mergesort {
public static int a[];
public static void merges (int work[], int low, int high) {
if (low==high)
return;
else {
int mid = (low+high)/2;
merges(work,low,mid);
merges(work,mid+1,high);
merge(work,low,mid+1,high);
}
}
public static void main (String[] args) {
int a[] = new int[] {64, 21, 33, 70, 12, 85, 44, 99, 36, 108};
merges(a,0,a.length-1);
for (int i=0; i<a.length; i++) {
System.out.println(a[i]);
}
}
public static void merge (int work[], int low, int high, int upper) {
int j = 0;
int l = low;
int mid = high-1;
int n = upper-l+1;
while (low<=mid && high<=upper)
if (a[low] < a[high])
work[j++] = a[low++];
else
work[j++] = a[high++];
while (low <= mid)
work[j++]=a[low++];
while (high <= upper)
work[j++] = a[high++];
for (j=0;j<n;j++)
a[l+j]=work[j];
}
}
它不起作用。编译后出现这样的错误:
java.lang.NullPointerException
at mergesort.merge(mergesort.java:45)
at mergesort.merges(mergesort.java:12)
at mergesort.merges(mergesort.java:10)
at mergesort.merges(mergesort.java:10)
at mergesort.merges(mergesort.java:10)
at mergesort.main(mergesort.java:27)
如何解决这个问题?
最佳答案
您有两个名为 a
的数组:
静态,mergesort.a
:
public static int a[];
以及 main 中的局部变量:
int a[]=new int[]{64,21,33,70,12,85,44,99,36,108};
当您在 merge
中使用 a
时,您使用的是从未初始化过的静态成员。
如果你想初始化mergesort.a
,你应该写
a = new int[]{64,21,33,70,12,85,44,99,36,108};
但是,这会让 merge
变得奇怪,因为它将有 work = a
作为参数,并引用静态 mergesort.a
>,这将是同一个数组。
感到困惑吗?我也是... :)
关于java - 我的合并排序实现中的运行时错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2948642/