如果我有一个字符串列表，我想将它们组合成一个具有重叠字符的字符串。如果没有剩余的重叠字符串，只需将其添加到末尾即可。这是一个过于简化的版本。
input = ['one', 'two']
output = 'twone'
我正在寻找某种方法来对输入列表中的任意数量的字符串执行此操作。
谢谢，
焦达米利奥
最佳答案
仅举一个微不足道的例子还不够好。这几乎是(农历)年中最未明确说明的问题。然而，假设重叠只能发生在两端，并且每个单词只被测试两次(针对当前输出的每一端)，并且您想要最大重叠，这将完成工作:
[修正错误后编辑]
def glue(a, b):
maxn = 0
for n in xrange(1, 1 + min(len(a), len(b))):
suffix = a[-n:]
prefix = b[:n]
if prefix == suffix:
maxn = n
# BUG: return maxn, a[:-maxn] + b
# FAILS when maxn == 0
# EXTRA TEST: ['nil', 'overlap']
return a + b[maxn:]
def multiglue(words):
if not words: return ""
result = words[0]
for word in words[1:]:
nx, rx = glue(result, word)
ny, ry = glue(word, result)
result = rx if nx > ny else ry
return result
tests = [line.split() for line in """
one
two one
one two
overlap nil
nil overlap
toad dog rabbit
frog ogham
ogham frog
hopper grasshopper
grass grasshopper person
foooo oooof
oooof foooo""".splitlines()]
for test in tests:
out = multiglue(test)
print test, repr(out)
输出:
[] ''
['one'] 'one'
['two', 'one'] 'twone'
['one', 'two'] 'twone'
['overlap', 'nil'] 'niloverlap'
['nil', 'overlap'] 'overlapnil'
['toad', 'dog', 'rabbit'] 'rabbitoadog'
['frog', 'ogham'] 'frogham'
['ogham', 'frog'] 'frogham'
['hopper', 'grasshopper'] 'grasshopper'
['grass', 'grasshopper', 'person'] 'grasshopperson'
['foooo', 'oooof'] 'foooof'
['oooof', 'foooo'] 'foooof'
关于Python将字符串组合成最短的字符串？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/4697508/