c# - n个连续整数的随机排列

Question

<分区>

Answer 1

首先创建一个所需大小的整数数组，并用递增的连续数字填充它；

int n = 10;
int[] array = new int[n + 1];
for (int i = 0; i <= n; i++)
{
    array[i] = i;
}
Shuffle(array);

你可以使用 Knuth/Fisher–Yates 洗牌

/// <summary>
/// Knuth shuffle
/// </summary>        
public void Shuffle(int[] array)
{
    Random random = new Random();
    int n = array.Count();
    while (n > 1)
    {
        n--;
        int i = random.Next(n + 1);
        int temp = array[i];
        array[i] = array[n];
        array[n] = temp;
    }
}