linux - 格式化awk的输出

Question

我正在编写 awk 脚本来确定字数。

awk '$1 ~/the/ {++c}END{print c}' FS=: br.txt
awk '$1 ~/not/ {++c}END{print c}' FS=: br.txt
awk '$1 ~/that/ {++c}END{print c}' FS=: br.txt

并对输出进行格式化，因此标题将是“the not that”，并且它们下面的行必须是每个单词的编号。我正在使用这个:

awk 'BEGIN { print "the not that"<br/> { printf "%-10s %s\n", $1, $1 }}' br.txt

问题是我无法获取单词下一行的单词数。我应该更改或添加什么？ 感谢您的努力

Answer 1

这是一个 awk，它应该可以满足您的需要。

awk '$1~/the/ {the++} $1~/not/ {not++} $1~/that/ {that++} END {print "the","not","that\n"the,not,that}' FS=: OFS="\t" br.txt

这是它的工作原理:

awk '
    $1~/the/ {the++}                        # If field `1` contains  `the` and `1` to variable `the`
    $1~/not/ {not++}                        # If field `1` contains  `not` and `1` to variable `not`
    $1~/that/ {that++}                      # If field `1` contains  `that` and `1` to variable `that`
END {                                       # When all file is read, do
    print "the","not","that\n"the,not,that} # Print header, and the value of variable  `the,not,that`
' FS=: OFS="\t" br.txt                      # Input field separator = `:`. Output separator = `<tab>`. Read file