我想同时使用 echo 和 grep 语句。我已经尝试了大部分内容，但无法获得准确的输出 如我所愿。
aa=$(grep -A100000 "2010-03-24" log.txt|grep "ORA")
echo "Ip-Address|Directory Name|${aa}" > output.txt
我正在查找日期，因为我想要当前日期之后的所有行，然后从中查找“ORA”。还有其他方法，但根据我的日志文件，这是最合适的方法。 我得到这样的输出。
10.46.162.86|ASD----Exception|2010-03-24 07 ORA-00001 - 80 -
173.45.230.59
2010-03-24 07:00:47 ORA-00942 - 80 - 173.45.230.59
2010-03-24 07:01:15 ORA-00001 - 80 - 173.45.230.59
2010-03-24 07:02:17 ORA-12849 - 80 - 173.45.230.59
2010-03-24 07:05:09 ORA-00001 - 80 - 173.45.230.59
理想的输出应该是这样的
10.46.162.86|ASD----Exception|2010-03-24 07 ORA-00001 - 80 -
173.45.230.59
10.46.162.86|ASD----Exception|2010-03-24 07:00:47 ORA-00942 - 80 -
173.45.230.59
10.46.162.86|ASD----Exception|2010-03-24 07:01:15 ORA-00001 - 80 -
173.45.230.59
10.46.162.86|ASD----Exception|2010-03-24 07:02:17 ORA-12849 - 80 -
173.45.230.59
10.46.162.86|ASD----Exception|2010-03-24 07:05:09 ORA-00001 - 80 -
173.45.230.59
我正在从不同目录的日志文件中获取 ORA。
输入就像
2010-03-22 07:00:47 ZZZZC941948879 RUFFLES 222.222.222.222 ORA-00001 -
80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+(Windows;+U;+Windows+NT+9.0;+en-
US;+rv:1.9.2.2)
2010-03-22 07:00:47 ZZZZC941948879 RUFFLES 222.222.222.222 GET
/2009/10/yep-twitter-down.ht
2010-03-22 07:00:48 ZZZZC941948879 RUFFLES 222.222.222.222 GET
/img/input-bg.jpg - 80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+
(Windows;+U;+Windows+NT+9.0;+en-
US;+rv:1.9.2.2)+Gecko/20100319+Firefox/3.9.2
2010-03-23 07:00:48 ZZZZC941948879 RUFFLES 222.222.222.222 ORA-00001 -
80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+(Windows;+U;+Windows+NT+9.0;+en-
US;+rv:1.9.2.2)+Gecko/20100319+Firefox/3.9.2
2010-03-23 07:00:48 ZZZZC941948879 RUFFLES 222.222.222.222 GET
/img/topnav-about.jpg - 80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+
(Windows;+U;+Windows+NT+9.0;+en-US;+rv:1.9.2.2)+Gecko/20100319
2010-03-23 07:00:48 ZZZZC941948879 RUFFLES 222.222.222.222 GET
/img/entry-hr.jpg - 80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+
(Windows;+U;+Windows+NT+9.0;+en-US;+rv:1.9.2.2)+Gecko/20100319+Firefox
2010-03-23 07:00:48 ZZZZC941948879 RUFFLES 222.222.222.222 ORA-00001 -
80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+(Windows;+U;+Windows+NT+9.0;+en-
US;+rv:1.9.2.2)+Gecko/20100319+Firefox/3.9.2
2010-03-24 07:00:48 ZZZZC941948879 RUFFLES 222.222.222.222 GET
/img/header-bg.jpg - 80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+
(Windows;+U;+Windows+NT+9.0;+en-US;+rv:1.9.2.2)+Gecko/20100319
2010-03-24 07:00:48 ZZZZC941948879 RUFFLES 222.222.222.222 GET
/img/bullet.gif - 80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+
(Windows;+U;+Windows+NT+9.0;+en-US;+rv:1.9.2.2)+Gecko/20100319+Firefox
2010-03-24 07:00:49 ZZZZC941948879 RUFFLES 222.222.222.222 ORA-00001 -
80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+(Windows;+U;+Windows+NT+9.0;+en-
US;+rv:1.9.2.2)+Gecko/20100319+Firefox/3.9.2
2010-03-24 07:00:49 ZZZZC941948879 RUFFLES 222.222.222.222 GET /img/bg-
module.jpg - 80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+
(Windows;+U;+Windows+NT+9.0;+en-US;+rv:1.9.2.2)+Gecko/20100319
2010-03-24 07:00:50 ZZZZC941948879 RUFFLES 222.222.222.222 ORA-00942 -
80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+(Windows;+U;+Windows+NT+9.0;+en-
US;+rv:1.9.2.2)+Gecko/20100319+Firefox/3.9.2
2010-03-24 07:00:50 ZZZZC941948879 RUFFLES 222.222.222.222 GET /img/bg-
sidebarul.jpg - 80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+
(Windows;+U;+Windows+NT+9.0;+en-US;+rv:1.9.2.2)+Gecko/20100319
2010-03-24 07:00:50 ZZZZC941948879 RUFFLES 222.222.222.222 ORA-00001 -
80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+(Windows;+U;+Windows+NT+9.0;+en-
US;+rv:1.9.2.2)+Gecko/20100319+Firefox/3.9.2
2010-03-24 07:00:51 ZZZZC941948879 RUFFLES 222.222.222.222 ORA-00942 -
80 - 98.88.35.133 HTTP/1.1 Mozilla/5.0+(Windows;+U;+Windows+NT+9.0;+en-
US;+rv:1.9.2.2)+Gecko/20100319+Firefox/3.9.2
这里的问题是，当我执行 grep 操作时，它会根据异常提取 100 行或更多行，并且我只能将 Ip-Address 和节点名称附加到一行。 此外，IP 地址和节点名称是在运行时生成的。 请建议一种获得所需输出的方法。 谢谢。
最佳答案
因为我只是知道特殊字符会出现在目录名称中，所以我更喜欢 awk 而不是 sed 以避免代码注入(inject)问题:
grep -A100000 "2010-03-24" log.txt | awk -v prefix="IP-Address|Directory name|" '/ORA/ { print prefix $0 }' > output.txt
相关部分是
awk -v prefix="IP-Address|Directory name|" '/ORA/ { print prefix $0 }'
使用 -v prefix=value，awk 会知道一个名为 prefix 且具有给定值的变量，并且 /ORA/{ print prefix $0 } 指示 awk 通过打印 prefix 后跟行(即 $0)来处理与正则表达式 ORA 匹配的所有行。
关于linux - 一起使用 echo 和 grep，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/28815094/