我将以下数据存储在一个文件中:
number1:0 number2=1 minnumber2number3:1 minnumber3:0 minnumber4:0 maxnumber2number3:1 maxnumber3:0 maxnumber4:0 no. of number5 per bucket:35 num:
number1:0 number2=0 minnumber2number3:3 minnumber3:3 minnumber4:11577215 maxnumber2number3:3 maxnumber3:3 maxnumber4:14707215 no. of number5 per bucket:6 num:
number1:0 number2=1 minnumber2number3:1 minnumber3:0 minnumber4:0 maxnumber2number3:3 maxnumber3:1 maxnumber4:1882188 no. of number5 per bucket:8 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:248 minnumber4:10000000 maxnumber2number3:2 maxnumber3:248 maxnumber4:10000000 no. of number5 per bucket:91 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:239 minnumber4:11641499 maxnumber2number3:2 maxnumber3:244 maxnumber4:2248700 no. of number5 per bucket:8999 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:251 minnumber4:2000000 maxnumber2number3:2 maxnumber3:251 maxnumber4:2000000 no. of number5 per bucket:8986 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:232 minnumber4:14775115 maxnumber2number3:1 maxnumber3:0 maxnumber4:0 no. of number5 per bucket:6385 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:253 minnumber4:9404695 maxnumber2number3:1 maxnumber3:0 maxnumber4:0 no. of number5 per bucket:8863 num:
number1:0 number2=1 minnumber2number3:3 minnumber3:3 minnumber4:14777215 maxnumber2number3:1 maxnumber3:0 maxnumber4:0 no. of number5 per bucket:2679 num:
现在我需要检索“每个桶的编号 5:”之后的所有数字并将它们相加。例如，我需要总结以下内容:
35
6
8
91
8999
8986
6385
8863
2679
我知道我可以使用像 python 这样的编程语言来做同样的事情，但是我正在学习 linux 命令是否有一些 linux 命令，比如 grep 等，可以帮助我做同样的事情。
最佳答案
你可以试试sed:
sed -e 's/^.*bucket://' | sed -e 's/[a-zA-Z]*:$//'
关于linux - 对字符串后的数字求和，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30658202/