Linux:使用 AWK 计算两个值之间的比率

Question

我有一个如下所示的文本文件:

abcd nasj uasdy 3452 2314134
abcd efgh sdfdsf 234553 9323454
abcd asdf asdfasdf 34545 5234523
abcd sdfa sadfad 435232434 3452435

现在我尝试使用 awk 计算第 5 列和第 4 列之间的比率，我试过这个:

BEGIN { printf "%10s %10s" "Column1:", "Ratio:%s" } 
        { printf "%10s %10f"  $1, ($6)/($5) }

但我一直收到错误提示:

awk: awkRatio.awk:1: fatal: not enough arguments to satisfy format string
    `%10s %10sColumn1:'
            ^ ran out for this one

Answer 1

看起来你在 printf "..." 部分后面漏了一个逗号 尝试:

BEGIN { printf "%10s %10s", "Column1:", "Ratio:" } 
    { printf "%10s %10f",  $1, ($5)/($4) }