linux - 如何在考虑其他文件的情况下显示文件的内容？

Question

我有包含以下内容的file1

{"name":"clio5", "value":"13"}
{"name":"citroen_c4", "value":"23"}
{"name":"citroen_c3", "value":"12"}
{"name":"golf4", "value":"16"}
{"name":"golf3", "value":"8"}

我有包含以下内容的file2

{"name":"clio5", "value":"14"}
{"name":"citroen_c4", "value":"25"}
{"name":"golf4", "value":"18"}

我想执行一个 shell 命令来显示 file1 和 file2 的内容。如果 name 同时存在于 file1 和 file2 中，那么我只想显示 file2 的相关行。

所以输出应该是这样的:

$command taking account file1 file2
{"name":"clio5", "value":"14"}
{"name":"citroen_c4", "value":"25"}
{"name":"citroen_c3", "value":"12"}
{"name":"golf4", "value":"18"}
{"name":"golf3", "value":"8"}

该命令不应编辑 file1 和 file2

编辑

file1 和file2 具有完全相同的内容格式:

{"name":"any", "value":"xx"}

命令越简单越好

命令可以包含grep、sed、awk

Answer 1

这是 awk 的一种方式:

awk -F"[:,]" '
NR==FNR { name[$2]=$0;next }
($2 in name) { delete name[$2]; print $0 }
END { for (left in name) print name[left] }' file1 file2

测试:

$ head file*
==> file1 <==
{"name":"clio5", "value":"13"}
{"name":"citroen_c4", "value":"23"}
{"name":"citroen_c3", "value":"12"}
{"name":"golf4", "value":"16"}
{"name":"golf3", "value":"8"}

==> file2 <==
{"name":"clio5", "value":"14"}
{"name":"citroen_c4", "value":"25"}
{"name":"golf4", "value":"18"}

$ awk -F"[:,]" '
NR==FNR { name[$2]=$0;next }
($2 in name) { delete name[$2]; print $0 }
END { for (left in name) print name[left] }' file1 file2
{"name":"clio5", "value":"14"}
{"name":"citroen_c4", "value":"25"}
{"name":"golf4", "value":"18"}
{"name":"golf3", "value":"8"}
{"name":"citroen_c3", "value":"12"}