linux - 如何在 bash 脚本中使用 awk 过滤 2 个日期之间的数据

Question

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Answer 1

对于像这样的古怪日期格式，我会将日期解析外包给 date 实用程序。

#!/usr/bin/awk -f

# Formats the timestamp as a number, so that higher numbers represent
# a later timestamp. This will not handle the time zone because date
# can't handle the o'clock notation. I hope all your timestamps use the
# same time zone, otherwise you'll have to hack support for it in here.
function datefmt(d) {
  # make d compatible with singly-quoted shell strings
  gsub(/'/, "'\\''", d)

  # then run the date command and get its output
  command = "date -d '" d "' +%Y%m%d%H%M%S"
  command | getline result
  close(command)

  # that's our result.
  return result;
}

BEGIN {
  # Field separator, so the part of the timestamp we'll parse is in $2 and $3
  FS = "[< >]+"

  # start, end set here.
  start = datefmt("19-Jan-2015 00:00:00")
  end   = datefmt("20-Jan-2015 23:59:59")
}

{
  # convert the timestamp into an easily comparable format
  stamp = datefmt($2 " " $3)

  # then print only lines in which the time stamp is in the range.
  if(stamp >= start && stamp <= end) {
    print
  }
}