我已经使用 new 在堆上分配了一个 vector :
std::vector<t*> *vec = new std::vector<t*>;
此 vector 包含类“t”的类对象,这些类对象是使用 new 创建的
t *ptr1 = new t();
t *ptr2 = new t();
t *ptr3 = new t();
t *ptr4 = new t();
现在,当我删除 vector 时,预计添加到其中的所有这些对象也应该被销毁,我的意思是:
std::vector<t*> *vec = new std::vector<t*>;
vec->push_back(ptr1);
vec->push_back(ptr2);
vec->push_back(ptr3);
vec->push_back(ptr4);
ptr1、ptr2、ptr3、ptr4 指向的内存也应该被释放。
但 Valgrind 将其显示为泄漏!!! Valgrind 有问题吗?
==15634==
==15634== HEAP SUMMARY:
==15634== in use at exit: 48 bytes in 8 blocks
==15634== total heap usage: 12 allocs, 4 frees, 128 bytes allocated
==15634==
==15634== LEAK SUMMARY:
==15634== definitely lost: 32 bytes in 4 blocks
==15634== indirectly lost: 16 bytes in 4 blocks
==15634== possibly lost: 0 bytes in 0 blocks
==15634== still reachable: 0 bytes in 0 blocks
==15634== suppressed: 0 bytes in 0 blocks
==15634== Rerun with --leak-check=full to see details of leaked memory
==15634==
==15634== For counts of detected and suppressed errors, rerun with: -v
==15634== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 2 from 2)
下面是完整的程序,供大家引用:
#include <iostream>
#include <vector>
using namespace std;
class t
{
int *ptr;
public:
t()
{
cout << "t's constructor" << endl;
ptr = new int(50);
}
~t()
{
cout << "t's destructor called" << endl;
delete ptr;
}
void func()
{
cout << "This is class t's function" << endl;
}
};
//void func(int *ptr, t* ptr1)
void func(t* ptr1)
{
//delete ptr;
delete ptr1;
}
int main( )
{
//int *ptr;
t *ptr1 = new t();
t *ptr2 = new t();
t *ptr3 = new t();
t *ptr4 = new t();
//ptr =new int(20);
//func(ptr, ptr1);
//func(ptr1);
std::vector<t*> *vec = new std::vector<t*>;
vec->push_back(ptr1);
vec->push_back(ptr2);
vec->push_back(ptr3);
vec->push_back(ptr4);
delete vec;
//delete ptr1; ===============> Are these required? Shouldn't delete vec take care?
// delete ptr2;
//delete ptr3;
//delete ptr4;
}
最佳答案
Now when i delete the vector, it's expected that all these objects which are added to it should get destroyed as well
它们是。您添加了指针,指针将被销毁。
不过,这并没有说明指针指向的东西。简而言之,您的假设是错误的。
您的选择:
-
delete
销毁 vector 之前的每个指针 - 使用智能指针
- 停止使用指针!停止使用动态分配!
std::vector<t>
在大多数情况下应该没问题。
关于c++ - 为什么 valgrind 显示泄漏,即使包含动态分配对象的 vector 已被释放?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24573891/