我想将 FTP session 与文件描述符相关联,文件描述符将在整个脚本中引用它。包括周期。
例如像这样的东西。但它没有做到。
#!/bin/bash
#start of script
exec {ftpdescriptor}<> >(lftp -u $ftpuser,$ftppass $ftpip/$ftptd)
# code
(echo "ls" 1>&"$ftpdecriptor")> myanswer
# code
echo "bye" 1>&"$ftpdecriptor"
exec {ftpdescriptor}>&-
exit 0
# end of script
它有效,但答案总是输出到标准输出..
最佳答案
这样解决了问题
# start of script
ftpout=$(mktemp)
$timetowaitftp
exec {ftpin}> >(lftp -u $ftpuser,$ftppass $ftpip/$ftptd > $ftpout)
printf >&$ftpin "set net:timeout 10\n"
function ftpio {
:>$ftpout
printf >&$ftpin "$1\n"
i=0
while [ ! $2 ] && [ ! -s $ftpout ] && [ $i -lt 10 ]; do
# echo "waiting answer from ftp 1 sec.."
sleep 1;
let i=i+1
done
}
# code
ftpio "cd /modx" "nowait" # no output of cd command.
ftpio "ls"
cat $ftpout
sleep 15
ftpio "pwd"
cat $ftpout
#ftpio "put /var/www/vhosts/modx/backups/20160121.113318.tar.gz" "nowait" # 12Gb
#ftpio "put /var/www/vhosts/modx/backups/20150930.092338.tar.gz" "nowait" # 800mb
# /code
# end of script
printf 1>&"$ftpin" "bye\n"
exec {ftpin}>&-
rm $ftpout
ftpin - 命名描述符
ftpout - 带有最后一个 ftp 应答的临时文件
关于linux - 如何在 bash 脚本中启动后台 lftp session ?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37875796/