php - 需要帮助分解 PHP 脚本/超过 max_execution_time

标签 php mysql linux apache

我有一个 PHP 脚本可以更新我网站上最流行和最流行的图片。该脚本旨在由 cron 作业每天运行一次,但我相信由于存储每个图像的每日统计信息的流量数据库(它主要依赖于该数据库)太大,脚本会超时。我在 hostgator 共享主机上,无法增加 max_execution_time,不幸的是,此时 VPS 或专用服务器不可行。如果有人对我可以使用以下脚本或数据库(目前超过 100mb)做什么以使其顺利运行有任何建议,我将不胜感激。您认为截断数据库是个好主意,还是只会弄乱图像数据的重要方面?

当前脚本如下:

<?php 
    $minute = date("i");

//  if($minute=='00') {
        include("../config/config.inc.php"); 
        include("../includes/meme-function.php");

        $date = date("Y-m-d");

        $query = mysql_query("SELECT `meme_id` FROM `$database1`.`memes`");
        while($row=mysql_fetch_assoc($query)) {
            $query_b = mysql_query("SELECT `views` FROM `$database2`.`daily_meme_stats` WHERE `meme_id` = '$row[meme_id]' ORDER BY `date` DESC");
            $c=0; $week=0; $month=0;
            while($row_b=mysql_fetch_assoc($query_b)) { 
                if($c<=5) {
                    $week=$week+$row_b['views'];
                }
                $month=$month+$row_b['views'];
            }
            mysql_query("UPDATE `$database1`.`memes` SET `views_day` = '0', `views_week` = '$week', `views_month` = '$month' WHERE `meme_id` = '$row[meme_id]' LIMIT 1");
            mysql_query("INSERT INTO `$database2`.`daily_meme_stats` SET `meme_id` = '$row[meme_id]', `date` = '$date'");
        }

        $query = mysql_query("SELECT `character_id` FROM `$database1`.`characters`");
        while($row=mysql_fetch_assoc($query)) {
            $query_b = mysql_query("SELECT `images` FROM `$database2`.`daily_char_stats` WHERE `char_id` = '$row[character_id]' ORDER BY `date` DESC");
            $c=0; $week=0; $month=0;
            while($row_b=mysql_fetch_assoc($query_b)) { 
                if($c<=5) {
                    $week=$week+$row_b['images'];
                }
                $month=$month+$row_b['images'];
            }
            mysql_query("UPDATE `$database1`.`characters` SET `images_today` = '0', `images_week` = '$week', `images_month` = '$month' WHERE `character_id` = '$row[character_id]' LIMIT 1");
            mysql_query("INSERT INTO `$database2`.`daily_char_stats` SET `char_id` = '$row[character_id]', `date` = '$date'");
        }

//  }

如果您有任何建议或想法,我将不胜感激。

最佳答案

我的想法:

  • 我想到的第一件事是:尝试将两个主要查询拆分到它们自己的文件中。
    • update-memes.php, update-chars.php
  • 可能会稍微提高 max_execution_time 或禁用它 set_time_limit(0);
  • 也许将功能转移到 MySQL 存储函数
  • 将所有统计(重新)计算移动到任务/工作队列中,例如 Gearman
    • 这将在后台持续工作并进行更新

Do you have a recommended file structure including opening and closing tags for each of these files.

您在拆分文件时遇到问题?我们开始吧:

更新-memes.php

<?php 
    // set_time_limit(0);

    include '../config/config.inc.php'; 
    include '../includes/meme-function.php';

    $date = date("Y-m-d");

    $query = mysql_query("SELECT `meme_id` FROM `$database1`.`memes`");

    while($row=mysql_fetch_assoc($query)) {

        $query_b = mysql_query("SELECT `views` FROM `$database2`.`daily_meme_stats` WHERE `meme_id` = '$row[meme_id]' ORDER BY `date` DESC");

        $c=0; $week=0; $month=0;

        while($row_b=mysql_fetch_assoc($query_b)) { 
            if($c<=5) {
                $week=$week+$row_b['views'];
            }
            $month=$month+$row_b['views'];
        }

        mysql_query("UPDATE `$database1`.`memes` SET `views_day` = '0', `views_week` = '$week', `views_month` = '$month' WHERE `meme_id` = '$row[meme_id]' LIMIT 1");

        mysql_query("INSERT INTO `$database2`.`daily_meme_stats` SET `meme_id` = '$row[meme_id]', `date` = '$date'");
    }
?>

update-chars.php

<?php
    // set_time_limit(0);

    include '../config/config.inc.php'; 
    include '../includes/meme-function.php';

    $date = date("Y-m-d");

    $query = mysql_query("SELECT `character_id` FROM `$database1`.`characters`");

    while($row=mysql_fetch_assoc($query)) {

        $query_b = mysql_query("SELECT `images` FROM `$database2`.`daily_char_stats` WHERE `char_id` = '$row[character_id]' ORDER BY `date` DESC");

        $c=0; $week=0; $month=0;   

        while($row_b=mysql_fetch_assoc($query_b)) { 
            if($c<=5) {
                $week=$week+$row_b['images'];
            }
            $month=$month+$row_b['images'];
        }

        mysql_query("UPDATE `$database1`.`characters` SET `images_today` = '0', `images_week` = '$week', `images_month` = '$month' WHERE `character_id` = '$row[character_id]' LIMIT 1");

        mysql_query("INSERT INTO `$database2`.`daily_char_stats` SET `char_id` = '$row[character_id]', `date` = '$date'");
    }
?>

顺便说一句:我删除了 $minute = date("i");//if($minute=='00') {.没有线索,如果你真的需要它。

计划

将这些行添加到您的 cronjobs(调整路径):

# run stats scripts every hour
00 * * * * /usr/local/bin/php /home/somewhere/update-memes.php
00 * * * * /usr/local/bin/php /home/somewhere/update-chars.php

关于php - 需要帮助分解 PHP 脚本/超过 max_execution_time,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30921239/

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