linux - 准备mysql语句时需要打印反斜杠

Question

我有一个文件需要转换成mysql插入语句，格式如下:

1
'Jan'
'Jame'
'O\'Leary'
'Bill'
''
NULL
1
'Eddie'
'Eddie'
'Unknown'
NULL
NULL
'John'
NULL
'Joseph'

我正在尝试使用以下代码来准备语句:

COUNTER=1;
echo "insert into database.table values " > full_statements.sql

while read LINE
do
    # There are 16 fields of information per insert statement.
    MODULUS=$(( $COUNTER % 16 ))
    # First piece of information needs to be in format "(value"
    if [ "$COUNTER" -eq 1 ]; then
        printf "("$LINE >> full_statements.sql
    # Last piece of information needs to be in format ",value),"        
    elif [ "$MODULUS" -eq 0 ]; then
        printf ","$LINE")," >> full_statements.sql
    # Interior pieces of information need to be in format ",value"
    else
        printf ","$LINE >> full_statements.sql
    fi

    # If we have a complete insert statement, reset the COUNTER.
    if [ "$COUNTER" -eq 16 ]; then
        COUNTER=1
    else
        ((COUNTER++))
    fi
done < binfile.new

不幸的是，我的结果如下:

insert into database.table values
(1,'Jan','Jame','O'Leary','Bill','',NULL,1,'Eddie','Eddie','Unknown',NULL,NULL,'John',NULL,'Joseph');

预期输出:

 insert into database.table values
    (1,'Jan','Jame','O\'Leary','Bill','',NULL,1,'Eddie','Eddie','Unknown',NULL,NULL,'John',NULL,'Joseph');

我用来转义 O'Leary 名字中的引号的反斜杠不会打印出来。我竭尽全力试图将这个“\”包含在输出中，但一直找不到答案。

帮助! :-)

Answer 1

在 awk 中。使用模 16 识别记录更改(即支持文件中超过 16 行)和三元运算符在内容之前和之后插入内容:

$ cat program.awk 
{
    printf "%s%s%s",(NR%16==1?"INSERT INTO DATABASE VALUES (":""),$0,(NR%16?",":");"ORS)
}

运行它:

$ awk -f program.awk file
INSERT INTO DATABASE VALUES (1,'Jan','Jame','O\'Leary','Bill','',NULL,1,'Eddie','Eddie','Unknown',NULL,NULL,'John',NULL,'Joseph');