linux - 如何使用 unix 命令将文本文件中的列打印为按行?

标签 linux unit-testing unix awk nawk

我有这样的文件..例如:

number,dac,amountdac,expdate,0
1111,1,0.000000,2010-07-21,0
1111,2,0.000000,2010-07-21,0
1111,3,0.000000,2010-07-21,0
1111,4,0.000000,2010-07-21,0
1111,5,0.000000,2010-07-21,0
1111,6,0.000000,2010-07-21,0
1111,7,0.000000,2010-07-21,0
1111,8,0.000000,2010-07-21,0
1111,9,0.000000,2010-07-21,0
1111,10,0.000000,2010-07-21,0
2222,1,50.000000,2010-07-21,0
2222,2,0.000000,2010-07-21,0
2222,3,0.000000,2010-07-21,0
2222,4,0.000000,2010-07-21,0
2222,5,0.000000,2010-07-21,0
2222,6,0.000000,2010-07-21,0
2222,7,0.000000,2010-07-21,0
2222,8,10.000000,2010-07-21,0
2222,9,0.000000,2010-07-21,0
2222,10,0.000000,2010-07-21,0
3333,1,0.000000,2010-07-21,0
3333,2,0.000000,2010-07-21,0
3333,3,0.000000,2010-07-21,0
3333,4,0.000000,2010-07-21,0
3333,5,0.000000,2010-07-21,0
3333,6,0.000000,2010-07-21,0
3333,7,0.000000,2010-07-21,0
3333,8,0.000000,2010-07-21,0
3333,9,200.000000,2010-07-21,0
3333,10,50.000000,2010-07-21,0

我想要这样的输出,所有 dac1 到 dac10 的第 1 列编号都是相同的。我给出的标题供您引用。在原始文件中我没有标题。

number,dac1,dac2,dac3,dac4,dac5,dac6,dac7,dac8,dac9,dac10,amountdac1,amountdac2,amountdac3,,amountdac4,amountdac5,amountdac6,amountdac7,amountdac8,amountdac9,,amountdac10,expdate1,expdate2,expdate3,expdate4,expdate5,expdate6,expdate7,expdate8,expdate9,expdate10,0
1111,1,2,3,4,5,6,7,8,9,10,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,0
2222,1,2,3,4,5,6,7,8,9,10,50.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,10.000000,0.000000,0.000000,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,0
3333,1,2,3,4,5,6,7,8,9,10,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,200.000000,50.000000,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,2010-07-21,0

最佳答案

awk -F"," '{ 
   a[$1];
   b[$1]=b[$1]","$2 
   c[$1]=c[$1]","$3
   d[$1]=d[$1]","$4
   e[$1]=e[$1]","$5 }
END{ for(i in a){ print i,b[i],c[i],d[i],e[i] } } ' file

关于linux - 如何使用 unix 命令将文本文件中的列打印为按行?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3299044/

相关文章:

linux - Jenkins 在远程 docker 代理中运行 sh 卡住

angular - 如何在 Angular4 中使用 Karma-Jasmine 测试导出功能

Python 单元测试的微妙错误

linux - 如何比较同一文件中的两列,并根据它将差异存储在新文件中与未更改的列中?

c++ - 多线程 Linux 应用程序中的互斥锁

linux - 如何根据网络接口(interface)名称获取 trace-cmd 报告(例如 : eth2)?

linux - 是否可以部分解压缩 .vcf 文件?

android - 模拟 WLResponse 抛出 HttpResponse 的 ClassNotFoundException

unix - 从 shell 脚本调用 Elasticsearch 以索引 pdf 文档

node.js - 格式化在管道中丢失