我在 Code::Blocks 中有一组 C++ 项目以及一个构建所有这些项目的脚本。该脚本如下所示:
codeblocks --build --target="release32" project1.cbp
codeblocks --build --target="release32" project2.cbp
codeblocks --build --target="release32" project3.cbp
...
有时,在构建其中一个项目时,Code::Blocks 无法完成该过程并出现错误:*** glibc 检测到 *** codeblocks: 损坏的双链表
。这与构建失败无关,这只是代码块中的一个错误,请参见此处:
https://bugs.launchpad.net/ubuntu/+source/codeblocks/+bug/764728
或在这里:
http://forums.codeblocks.org/index.php?topic=16883.0
我想要做的一个解决方法是在命令仍在运行时解析命令的输出,找到字符串“codeblocks:损坏的双链表”,然后终止代码块以让脚本构建其他项目并完成。
我怎样才能做到这一点?
最佳答案
有点 hacky,但这对你有用吗(bash
)?
这只是为了模拟代码块二进制文件(./codeblocks
):
$ cat codeblocks
#!/bin/bash
num=$RANDOM
((num %= 2))
case "$num" in
0)
echo "codeblocks finished successfully: $*"
exit 0
;;
1)
echo "*** glibc detected *** codeblocks: corrupted double-linked list" 1>&2
while true; do
sleep 1
done
;;
esac
这是实际的测试脚本(test.sh
):
$ cat test.sh
#!/bin/bash
run_codeblocks()
{
until (
subshell_pid=$BASHPID
echo "trying to run 'codeblocks $*'"
./codeblocks "$@" 2>&1 | while read line; do
echo "[${line}]"
[[ ${line} == *"*** glibc detected ***"* ]] && kill $subshell_pid
done
return 0
); do
:
done
}
echo "running codeblocks ..."
run_codeblocks 1
run_codeblocks 2
run_codeblocks 3
echo "... done"
您将对 codeblocks
的调用包装在子 shell 中,grep 其输出,如果一行与您指定的错误匹配,则会终止该子 shell。基本上就是你所描述的。
$ ./test.sh
running codeblocks ...
trying to run 'codeblocks 1'
[codeblocks finished successfully: 1]
trying to run 'codeblocks 2'
[*** glibc detected *** codeblocks: corrupted double-linked list]
./test.sh: line 4: 29889 Terminated ( subshell_pid=$BASHPID; echo "trying to run 'codeblocks $*'"; ./codeblocks "$@" 2>&1 | while read line; do
echo "[${line}]"; [[ ${line} == *"*** glibc detected ***"* ]] && kill $subshell_pid; return 0;
done )
trying to run 'codeblocks 2'
[*** glibc detected *** codeblocks: corrupted double-linked list]
./test.sh: line 4: 29892 Terminated ( subshell_pid=$BASHPID; echo "trying to run 'codeblocks $*'"; ./codeblocks "$@" 2>&1 | while read line; do
echo "[${line}]"; [[ ${line} == *"*** glibc detected ***"* ]] && kill $subshell_pid; return 0;
done )
trying to run 'codeblocks 2'
[codeblocks finished successfully: 2]
trying to run 'codeblocks 3'
[*** glibc detected *** codeblocks: corrupted double-linked list]
./test.sh: line 4: 29903 Terminated ( subshell_pid=$BASHPID; echo "trying to run 'codeblocks $*'"; ./codeblocks "$@" 2>&1 | while read line; do
echo "[${line}]"; [[ ${line} == *"*** glibc detected ***"* ]] && kill $subshell_pid; return 0;
done )
trying to run 'codeblocks 3'
[codeblocks finished successfully: 3]
... done
关于Linux shell 杀死命令,同时仍然根据输出运行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15922315/