linux - 计算文件中 2 个字符串之间匹配的行数

Question

我有一个挑战。我有这段文字:

characteristic "type"
   value "A"
   value "B"
   value "C" 
   default-value "B" 
exit 
characteristic "active"
   value "no"
   value "yes"
   default-value "no" 
exit
characteristic "traffic"
   value "disabled" 
   value "enabled"
   default-value "enabled"
exit
characteristic "quota" 
   value "enabled"
   default-value "disabled"
exit
characteristic "redirect"
   value "disabled"
   value "enabled"
   default-value "disabled"
exit

我想知道“特征”和“退出”之间的“值”一词出现了多少次。所以，我希望是这样的:

3
2
2
1
2

我尝试使用 sed 和 grep 但我无法得到 sed 给我返回 nth ' -n -e "/^characteristic/,/^exit/p"'。我确信 bash 可以在没有很多do while/done 和if 的情况下做到这一点。

感谢您的帮助。

Answer 1

我会说:

awk '$1 == "characteristic" { ctr = 0 } $1 == "exit" { print ctr } $1 == "value" { ++ctr }' filename

非常简单:

$1 == "characteristic" { ctr = 0 }  # Start of a new section: reset counter
$1 == "exit" { print ctr }          # end of section: print counter
$1 == "value" { ++ctr }             # value line: increase counter