linux - 如何在 linux 中打印字符串中的特定字符？

Question

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Answer 1

要从字符串中删除后缀模式，请使用语法:${parameter%%word}。

例子:

$ foo=ggc-clusterdb01.rvd.ukd.com
$ echo ${foo%%01.rvd.ukd.com}     
ggc-clusterdb

您也可以使用通配符:

$ echo ${foo%%0*.rvd.ukd.com}     
ggc-clusterdb

要删除点后的所有内容:

$ echo ${foo%%.*}
ggc-clusterdb

来自 man bash 的解释:

${parameter%%word}

Remove matching suffix pattern. The word is expanded to produce a pattern just as in pathname expansion. If the pattern matches a trailing portion of the expanded value of parameter, then the result of the expansion is the expanded value of parameter with the shortest matching pattern (the ''%'' case) or the longest matching pattern (the ''%%'' case) deleted.