linux - 如何使用 seq 填充小数位

Question

我不知道如何使用 seq 来填充小数位。这是我根据网上找到的内容尝试的...

for U in $(seq -f "%0.2g" 0 0.1 1)

但它无法工作。

我正在寻找输出，

0.00
0.10
0.20
...

Answer 1

file format notation 中的

g删除尾随零。你想要f:

seq -f "%0.2f" 0 0.1 1

结果

0.00
0.10
0.20
0.30
0.40
0.50
0.60
0.70
0.80
0.90
1.00

规范的相关摘录如下:

f,F

The floating-point number argument shall be written in decimal notation in the style [-]ddd.ddd, where the number of digits after the radix character (shown here as a decimal point) shall be equal to the precision specification.

e,E

The floating-point number argument shall be written in the style [-]d.ddde±dd (the symbol '±' indicates either a <plus-sign> or minus-sign), where there is one digit before the radix character (shown here as a decimal point) and the number of digits after it is equal to the precision.

g,G

The floating-point number argument shall be written in style f or e (or in style F or E in the case of a G conversion specifier), with the precision specifying the number of significant digits. [...] Trailing zeros are removed from the result.