我正在编写一个程序，其中有两个我需要使用的库:v8 和 v8-juice。不幸的是，v8-juice 不能编译为静态库，因为它与模板有关。它还有一些其他怪癖，需要将 v8 编译为共享对象。
因此，当我编译我的程序时，我最终得到了运行可执行文件所需的两个共享对象。我的问题是，有没有一种方法可以包含这些共享对象而无需在 linux 下安装它们？抱歉，如果这是一个新问题，我是 C++ 的新手。
最佳答案
共享库可以与您的可执行文件位于同一文件夹中。 man ld.so:
$ORIGIN and rpath
ld.so understands the string $ORIGIN (or equivalently ${ORIGIN}) in an
rpath specification (DT_RPATH or DT_RUNPATH) to mean the directory con-
taining the application executable. Thus, an application located in
somedir/app could be compiled with gcc -Wl,-rpath,'$ORIGIN/../lib' so
that it finds an associated shared library in somedir/lib no matter
where somedir is located in the directory hierarchy. This facilitates
the creation of "turn-key" applications that do not need to be
installed into special directories, but can instead be unpacked into
any directory and still find their own shared libraries.
关于c++ - linux下C++中无需安装的共享对象和包含，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/4742003/