linux - 在带有标题的 block 中分组的行中的数字总和(使用 Bash 和 AWK)

Question

假设我有以下示例输出:

Node hostabc foofoofoo
        1 foo
        1 ...
        1 ...
        1 ...
        1 ...
        5 ...
Node hostcde ...
        1 ...
        10 ...

如何获得每个主机的数字总和(不使用临时文件，仅使用 Bash 和 AWK)？

例如:

hostabc     10
hostcde     11

Answer 1

您可以使用以下 awk 命令:

awk '/^Node/{n=$2;next}{t[n]+=$1}END{for(n in t){print n,t[n]}}' file

更好地解释为多行脚本:

# If the line starts with 'Node'
/^Node/ {
    # Set n(ame) to the value of the second field
    n=$2
    # No further actions on this line
    next
}
{
    # Add the value of the first field to t(otals)[n(name)]
    t[n]+=$1
}
# Once the end of input has been reached
END{
    # Iterate trough t(otals) keys
    for(n in t) {
        # Print the total along with the name
        print n,t[n]
    }
}