我正在使用此页面中的代码 http://code.google.com/apis/contacts/docs/1.0/developers_guide_js.html获取 gmail 联系人列表。实际上它工作正常，但我得到名称、地址等数据，就像一个简单的字符串，以“\n”作为分隔符，例如:
<script type="text/javascript">
var contactsService;
var scope = 'https://www.google.com/m8/feeds';
function setupContactsService() {
//contactsService = new google.gdata.contacts.ContactsService('exampleCo-exampleApp-1.0');
contactsService = new google.gdata.contacts.ContactsService('GoogleInc-jsguide-1.0');
}
function getMyContacts() {
var contactsFeedUri = 'https://www.google.com/m8/feeds/contacts/default/full'; //?max-results=9999&alt=json&v=3.0
var query = new google.gdata.contacts.ContactQuery(contactsFeedUri);
setupContactsService();
contactsService.getContactFeed(query, handleContactsFeed, handleError);
}
var handleContactsFeed = function(result) {
var entries = result.feed.entry;
for (var i = 0; i < entries.length; i++) {
var entry = entries[i];
var addrs = entry.getPostalAddresses();
var name = entry.getTitle();
// logging
console.log(addrs[0]);
console.log(name);
}
}
function handleError(e) {
alert(e.cause ? e.cause.statusText : e.message);
}
</script>
它给了我一个对象，其中的名称和地址值是简单的字符串。
我能否以某种方式获取类似关联数组格式的数据，其中地址将包含街道、邮政编码、城市、国家/地区的单独值；并命名名字、姓氏等的单独值。
喜欢:
{
"type": "address",
"value":
{
"street": "Starret 1234",
"city": "City name",
"stateOrProvince": "ca",
"postalCode": "73000",
"country": "USA"
}
},
{
"type": "name",
"value":
{
"firstName": "Allen",
"lastName" : "Iverson",
.....
}
}
提前致谢!
最佳答案
似乎我找到了答案，为了获得更详细和格式化的信息，需要为 google.gdata.contacts.ContactQuery 添加额外的参数到 contactsFeedUri。
这个附加参数是:?v=3.0 所以在我的例子中函数看起来像:
function getMyContacts() {
var contactsFeedUri = 'https://www.google.com/m8/feeds/contacts/default/full?v=3.0&alt=json';
var query = new google.gdata.contacts.ContactQuery(contactsFeedUri);
setupContactsService();
contactsService.getContactFeed(query, handleContactsFeed, handleError);
}
为了获取必要的数据，我创建了一个简单的对象，它对某些人可能很有用:
function contactEntry(entry) {
this.entry = entry;
this.testEntry = function() {
alert( 'test entry' )
};
this.getFirstName = function() {
if ((entry.gd$name == null) || (entry.gd$name.gd$givenName == null) || (entry.gd$name.gd$givenName.$t == null)) {
return '';
} else {
return entry.gd$name.gd$givenName.$t;
}
};
this.getLastName = function() {
if ((entry.gd$name == null) || (entry.gd$name.gd$familyName == null) || (entry.gd$name.gd$familyName.$t == null)) {
return '';
} else {
return entry.gd$name.gd$familyName.$t;
}
};
this.getAdditionalName = function() {
if ((entry.gd$name == null) || (entry.gd$name.gd$AdditionalName == null) || (entry.gd$name.gd$AdditionalName.$t == null)) {
return '';
} else {
return entry.gd$name.gd$familyName.$t;
}
};
this.getEmail = function() {
if ((entry.gd$email == null) || (entry.gd$email.length == 0) || (entry.gd$email[0].address == null)) {
return '';
} else {
return entry.gd$email[0].address;
}
};
this.getStreet = function() {
if (!this._addrExists() || (entry.gd$structuredPostalAddress[0].gd$street == null)) {
return '';
} else {
return entry.gd$structuredPostalAddress[0].gd$street.$t;
}
};
this.getCity = function() {
if (!this._addrExists() || (entry.gd$structuredPostalAddress[0].gd$city == null)) {
return '';
} else {
return entry.gd$structuredPostalAddress[0].gd$city.$t;
}
};
this.getCountry = function() {
if (!this._addrExists() || (entry.gd$structuredPostalAddress[0].gd$country == null)) {
return '';
} else {
return entry.gd$structuredPostalAddress[0].gd$country.$t;
}
};
this.getPostcode = function() {
if (!this._addrExists() || (entry.gd$structuredPostalAddress[0].gd$postcode == null)) {
return '';
} else {
return entry.gd$structuredPostalAddress[0].gd$postcode.$t;
}
};
this.getPhone = function() {
if ((entry.gd$phoneNumber == null) || (entry.gd$phoneNumber.length == 0) || (entry.gd$phoneNumber[0].$t == null)) {
return '';
} else {
return entry.gd$phoneNumber[0].$t
}
};
this.getOrganization = function() {
if ((entry.gd$organization == null) || (entry.gd$organization.length == 0) || (entry.gd$organization[0].getOrgName() == null)) {
return '';
} else {
return entry.gd$organization[0].getOrgName().getValue();
}
};
this.getBirthday = function() {
if ((entry.gContact$birthday == null) || (entry.gContact$birthday.when == null)) {
return '';
} else {
return entry.gContact$birthday.when;
}
};
this.getEvent = function() {
if ((entry.gContact$event == null) || (entry.gContact$event.length == 0) || (entry.gContact$event[0].gd$when == null)) {
return '';
} else {
return entry.gContact$event[0].gd$when.startTime;
}
};
// protected methods
this._addrExists = function() {
if ((entry.gd$structuredPostalAddress == null) || (entry.gd$structuredPostalAddress.length == 0)) {
return false;
}
return true;
};
}
可以这样使用:
var handleContactsFeed = function(result) {
var entries = result.feed.entry;
var contact = new contactEntry(entries[0]);
var address = {};
address['fname'] = contact.getFirstName();
address['lname'] = contact.getLastName() + (contact.getAdditionalName() != '' ? ' ' + contact.getAdditionalName() : '');
address['address'] = contact.getStreet();
address['city'] = contact.getCity();
address['country'] = contact.getCountry();
address['zip'] = contact.getPostcode();
address['phone'] = contact.getPhone();
address['mail'] = contact.getEmail();
address['organization'] = contact.getOrganization();
address['birthday'] = contact.getBirthday();
address['event'] = contact.getEvent();
}
关于javascript - 如何使用 javascript Google Contact API 以更详细的格式导入 gmail 联系人数据？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/6691921/