javascript - 如何处理ajax响应中的内部服务器错误

Question

当我用 JavaScript(使用 JQuery)发送 Ajax 请求时，它有时会抛出一个我无法捕获的内部服务器错误。错误显示在浏览器中。我什至尝试将 ajax 调用包装在 try - catch block 中。我该如何处理 Ajax 错误？

编辑 这是我的代码:

$.post('/multi/getGameStatus', function(data) {
    if(data && data.game) {
        settings.game = data.game;
        setStartRacePopupUI.call(this, data);
        // remove all racers
        removePlayers.call();
        for(var i=0;i<settings.game.players.length;i++) {
            var player = settings.game.players[i];
            var isme = (player.id == settings.playerId);
            addPlayer.call(this, player, isme, i);
        }

        if (settings.game.gameStatus == "OPEN") {
            setTimeout(refreshPlayers, refreshPlayersInterval, nextStatus);
        } else if(settings.game.gameStatus == "IN_GAME") {
            counterToGameStart = data.sts;
            gameFllow(nextStatus);
        }
    }
});

即使我使用错误处理程序，页面上仍然会出现 JS 错误

Answer 1

http://api.jquery.com/jQuery.ajax/

...For convenience and consistency with the callback names used by $.ajax(), jqXHR also provides .error(), .success(), and .complete() methods.

The jqXHR.success(), jqXHR.error(), and jqXHR.complete() callbacks will be deprecated in jQuery 1.8. To prepare your code for their eventual removal, use jqXHR.done(), jqXHR.fail(), and jqXHR.always() instead.

// Assign handlers immediately after making the request,
// and remember the jqxhr object for this request
var jqxhr = $.ajax( "example.php" )
    .done(function() { alert("success"); })
    .fail(function() { alert("error"); })