javascript - 覆盖函数的 toString 函数

Question

我想通过 the answer 生成一个 GUID 字符串.

'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function(c) {
    var r = Math.random()*16|0, v = c == 'x' ? r : (r&0x3|0x8);
    return v.toString(16);
});

现在，我想将它放入 toString 函数中，例如:GUID.NewGuid().toString()。

我试过了(没用):

let GUID = function () {};
GUID.NewGuid = function () {};

GUID.NewGuid.prototype.toString = function () {
    let guid = 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function (c) {
        let r = Math.random() * 16 | 0, v = c === 'x' ? r : (r & 0x3 | 0x8);
        return v.toString(16);
    });

    return guid;
};

Uncaught TypeError: Cannot read property 'toString' of undefined console.log(GUID.NewGuid().toString());

我想要实现的目标:使用语法 GUID.NewGuid().toString() 生成一个 id。

如何解决？

Answer 1

你需要一个 instance类(class)的。

var guid = new GUID.NewGuid;

let GUID = function () {};
GUID.NewGuid = function () {};

GUID.NewGuid.prototype.toString = function () {
    let guid = 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function (c) {
        let r = Math.random() * 16 | 0, v = c === 'x' ? r : (r & 0x3 | 0x8);
        return v.toString(16);
    });
    return guid;
};

var guid = new GUID.NewGuid;

console.log(guid.toString());