javascript - 检查元素(DOM 节点)是否是 sibling

Question

如何判断两个DOM元素是否是兄弟？

示例 DOM 结构:

<div>
    <a></a>
    <b></b>
    <p></p>
</div>
<i></i>

测试是否<b>是 <a> 的 sibling 但不是 <i>

Answer 1

jQuery:

var a = $('a'),
    b = $('b'),
    i = $('i');

a.siblings().is(b); // true (since "b" is sibling of "a")
a.siblings().is(i); // false (since "i" is sibling of "div" and not of "a")
a.siblings().is(a); // false (can't be singling of itself)

Vanilla :

const elm_p = document.querySelector('p');
const elm_a = document.querySelector('a');
const elm_i = document.querySelector('i');

const areSiblings = (elm1, elm2) => 
  elm1 != elm2 && elm1.parentNode == elm2.parentNode;

// tests
[
  [elm_p, elm_a], // true
  [elm_a, elm_p], // true
  [elm_a, elm_a], // false
  [elm_a, elm_i]  // false
].forEach(([a,b]) => console.log(areSiblings(a,b)))

<div>
    <a></a>
    <b></b>
    <p></p>
</div>
<i></i>